unclear & not working...
>
> Regards,
>
> Toby Butzon
> [ criticism spurs improvement ]
>
> - Original Message -
> From: "Todd Cary" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Tuesday, January 09, 2001 11:04 PM
> Subject: Re: [PH
rs improvement ]
- Original Message -
From: "Todd Cary" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, January 09, 2001 11:04 PM
Subject: Re: [PHP] Passing a query result
: Whoops! I forgot the code!!
:
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To unsubs
Whoops! I forgot the code!!
function db_get_n_row($dbh, $row, $currentRow, $nextRow) {
while (($row) && ($currentRod != $nextRow)) {
ibase_fetch_row($row);
$currentRow++;
if ($currentRow == $nextRow) {
return $row;
} else {
return 0;
};
};
gt;
> Sent: Tuesday, January 09, 2001 10:47 PM
> Subject: [PHP] Passing a query result
>
> : I need to pass a query result to a functionas demonstrated below. I get
> : the error message that $row is not a result type. Is there a way around
> : this?
> :
> :
Working with what sort of database?
Toby Butzon
[ criticism spurs improvement ]
- Original Message -
From: "Todd Cary" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, January 09, 2001 10:47 PM
Subject: [PHP] Passing a query result
: I need to pa
I need to pass a query result to a functionas demonstrated below. I get
the error message that $row is not a result type. Is there a way around
this?
Todd
--
Todd Cary
Ariste Software
[EMAIL PROTECTED]
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