On Mon, 27 Oct 2003 13:00:19 -, you wrote:
$n is created /outside/ the function.
> $n = 1;
So you can't use it here. It's not in scope.
> $array[$n][$colname] = $value;
>But when I run this script, it looses the first row and doesn't really
That's because you get the first row here.
>
* Thus wrote Tom Wollaston ([EMAIL PROTECTED]):
> I am having problems sorting stuff into an array. It doesn't seem to work
> quite how everything I read says it should. It is probably my understanding
> of it but either way I don't really know whats going on.
Did you not read my response to your
I am having problems sorting stuff into an array. It doesn't seem to work
quite how everything I read says it should. It is probably my understanding
of it but either way I don't really know whats going on.
I am trying to put everything out of a table into an array so I can call up
the individual
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