Remove the double-double quotes and the newline around $image:
> $img = GetImageSize(""$image\n"");this is Line 13
It should look like:
$img = GetImageSize($image);
There is no need to double quote a variable when passing as a parm. You
would want to double quote a variable
Hi everybody,
I'm a french newbie in PHP and I'm trying to resolve this :
$num champs dans la ligne $row: ";
//$row++;
for ($c=0; $c<$num; $c++) {
//print $data[$c] . "";
$image = $data[$c];
$img = GetImageSize(""$image\n"");this is Line 13
print $image;
print $img;
}
}
fcl
2 matches
Mail list logo
