> Warning: Unable to jump to row 0 on MySQL result index 2 in
> /home/sites/site3/web/showthumb on line 71
>
> --here is my code
Change it to look like this:
> $connetion = mysql_connect("localhost","cel34243","s2343223") or
die($php_errormsg);
> $query = "select images from celeb where name=\"$
hi
i get this message when i am trying to load some data from mysql.
Warning: Unable to jump to row 0 on MySQL result index 2 in
/home/sites/site3/web/showthumb on line 71
--here is my code
$connetion = mysql_connect("localhost","cel34243","s2343223");
$query = "select images from celeb where n
On Thu, 8 Mar 2001 02:38, Deependra B. Tandukar wrote:
> Greetings!
>
> I am trying to compile MySQL. what I did are:
> tar -xvzf mysql-3.23.33.tar.gz
> cd mysql-3.23.33
> ./configure --prefix=/usr/local/mysql
> then it startx to work and inerrupt and says
> testing gcc working: no
> configure: e
Greetings!
I am trying to compile MySQL. what I did are:
tar -xvzf mysql-3.23.33.tar.gz
cd mysql-3.23.33
./configure --prefix=/usr/local/mysql
then it startx to work and inerrupt and says
testing gcc working: no
configure: error: installation or configure problem: c compiler can not create
execut
4 matches
Mail list logo