Hi JS et al...
Thanks! This was what I was looking for. Also thanks for the color code, much
smaller!
JIM
On Saturday 02 November 2002 18:54, Jonathan Sharp wrote:
> try this:
>
> -js
>
>
> $i = 0;
> while ( $myrow = mysql_fetch_array($result) )
> {
> $c = ( ++$i % 2 ? 'yellow' : 'white
When you run mysql_query, it just sends back a resource id to the result
set. To get the data, use something like mysql_fetch_array()
$sql = "SELECT * FROM `myDataBase.myTable`";
if ( $result = @mysql_query ( $sql ) ) {
while ( $data = @mysql_fetch_array ( $result, MYSQL_ASSOC ) ) {
print_r (
try this:
-js
";
printf('Delete',
$PHP_SELF, $myrow['id'] );
$q = ceil( 4/(int)date('n', strtotime($mydata['date']) ));
printf('%s%s%s',
'update-inv.php', $myrow['id'], $myrow['name'], $myrow['details'], $q);
}
?>
Jim Hatridge wrote:
> HI all,
>
> In the code below I'm trying to
HI all,
In the code below I'm trying to get the last column to show 1, 2, 3, or 4
according to which quarter of the year it is. But all it shows in that column
is " Resource ID # X". The X starts with #3 and goes to 18. There are (at the
moment) 15 items in the table. Any ideas what's wrong?
Tha
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