=0;
> $year = date("Y");
> while($x < 20)
> {
> $year = $year+1;
> print($year . "\n");
> $x++;
> }
> ?>
>
> Try that.
>
> Tyler
>
> > -Original Message-
> > From: Jason Caldwell [mailto:[EMAIL PROTECT
Hi Jason,
You might want to put the '+$x' outside the date().
$year = date("Y") + $x;
Greetings,
Michael.
> I'm trying to figure out how to add to the year:
>
> for($x=0; $x<20; $x++)
> {
> $year = date("Y" + $x);
> print($year . "\n");
> }
>
> I've tried several variations on the a
On Wed, 23 May 2001 13:49, Jason Caldwell wrote:
> I'm trying to figure out how to add to the year:
>
> for($x=0; $x<20; $x++)
> {
> $year = date("Y" + $x);
> print($year . "\n");
> }
>
> I've tried several variations on the above and cannot get the year to
> come out.
>
> Any suggestions?
Try that.
Tyler
> -Original Message-
> From: Jason Caldwell [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, May 22, 2001 11:20 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP] Date (Year) .. adding..
>
>
> I'm trying to figure out how to add to the
I'm trying to figure out how to add to the year:
for($x=0; $x<20; $x++)
{
$year = date("Y" + $x);
print($year . "\n");
}
I've tried several variations on the above and cannot get the year to come
out.
Any suggestions?
Thanks
Jason
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