Thanks Chris. It has been a while since I used this command. Ron
On Mon, 2009-04-20 at 13:27 +1000, Chris wrote:
> Ron Piggott wrote:
> > Where $date_reference is 2009-04-18 the following code gives me a day of
> > 1969-12-30. How do I get it to be 2009-04-17?
> >
> > $previous_date = strto
Ron Piggott wrote:
Where $date_reference is 2009-04-18 the following code gives me a day of
1969-12-30. How do I get it to be 2009-04-17?
$previous_date = strtotime("-1 days", $date_reference);
$previous_date = date('Y-m-d', $previous_date);
echo $previous_date; outputs 1969-12-30
Ron
Ron Piggott wrote:
Where $date_reference is 2009-04-18 the following code gives me a day of
1969-12-30. How do I get it to be 2009-04-17?
$previous_date = strtotime("-1 days", $date_reference);
$previous_date = date('Y-m-d', $previous_date);
Slightly wrong syntax.
$previous_date = strtotime
Where $date_reference is 2009-04-18 the following code gives me a day of
1969-12-30. How do I get it to be 2009-04-17?
$previous_date = strtotime("-1 days", $date_reference);
$previous_date = date('Y-m-d', $previous_date);
echo $previous_date; outputs 1969-12-30
Ron
Hi Robert-
You may want to spend a little more time
with basic PHP tutorials, see:
http://www.php.net/links
To answer your question, the problem is
with variable/string use, not any PHP
functions. $blah in particular.
Use quotes around strings:
$blah = '2002-05-02';
Read about string
On 3 May 2002 at 12:04, ROBERT MCPEAK wrote:
> $blah=2002-05-02;
> $thedate = date("D, M d, Y", strtotime($blah));
> $echo "$thedate";
$blah will = 1995. Try putting quotes around the date...
$blah = "2002-05-02";
--
Stuart
--
PHP General Mailing List (http://www.php.net/)
To unsubscr
Because your strtotime() call is returning 0. Replace the '-' with '/'
and I bet it would work.
-Rasmus
On Fri, 3 May 2002, ROBERT MCPEAK wrote:
> Running PHP3 on a Linux box and I've got trouble with date().
>
> Here's the code:
>
> $blah=2002-05-02;
> $thedate = date("D, M d, Y", strtotime($
Running PHP3 on a Linux box and I've got trouble with date().
Here's the code:
$blah=2002-05-02;
$thedate = date("D, M d, Y", strtotime($blah));
$echo "$thedate";
Why is $thedate resolving to Wed, Dec 31, 1969.
Thanks!
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit
8 matches
Mail list logo