You could also try:
if(! ereg('^http://', $url))
$url = 'http://' . $url;
-JAson Garber
At 11:15 PM 11/20/2001 +0100, Daniel Alsén wrote:
> > How about:
> >
> > if (substr($url,0,7) <> "http://";)
> > $url = "http://"; . $url;
>
>Thanks!
>
>That´s just the function i am looking f
Correct, the third parameter is for the number of characters to read,
nothing means entire string.
Function details can be found here:
http://download.php.net/manual/en/function.substr.php
> > How about:
> >
> > if (substr($url,0,7) <> "http://";)
> > $url = "http://"; . $url;
>
> Thanks!
>
> How about:
>
> if (substr($url,0,7) <> "http://";)
> $url = "http://"; . $url;
Thanks!
That´s just the function i am looking for. I looked it up in the manual.
Correct me if i am wrong - if i don´t set the second parameter in substr it
just continues to read until the variable is finished?
How about:
if (substr($url,0,7) <> "http://";)
$url = "http://"; . $url;
> Hi,
>
> which function would i use to check if a certain value is in the contents
of
> a variable?
>
> I have a form where the users submits url's. I need the url with http://
in
> the beginning. Since there is more
Hi,
which function would i use to check if a certain value is in the contents of
a variable?
I have a form where the users submits url's. I need the url with http:// in
the beginning. Since there is more data after the http:// i can´t just do a
simple if-statement. So what do i do?
After i dete
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