Martin Scotta wrote:
> Why are you ussing GD?
> All you need is output the image to the browser?
>
> try this... I didn't test/run this code, but it may work...
>
> public function showPicture( $id ) {
> header('Content-type:' . mime_content_type( $this->updir . $id .
> '.png' ) );
>
Ash, Martin,
Seems you are both wandering around the obvious problem...
I suspect that $tipo (in the next line) is *supposed* to be $type - sounds like
a partial Italian translation to me...
So given that $type="imagecreatefrompng" (for example, if the mime check returns
'png' - not very reliabl
Why are you ussing GD?
All you need is output the image to the browser?
try this... I didn't test/run this code, but it may work...
public function showPicture( $id ) {
header('Content-type:' . mime_content_type( $this->updir . $id .
'.png' ) );
readfile( $this->updir . $id . '.png' )
On Tue, 2009-07-14 at 14:16 -0300, Martin Scotta wrote:
> On Tue, Jul 14, 2009 at 1:48 PM, Ashley
> Sheridan wrote:
> > On Tue, 2009-07-14 at 13:41 -0300, Martin Scotta wrote:
> >> He is calling the function by variable
> >>
> >> something like this
> >>
> >> $func = 'var_dump';
> >>
> >> $func( ne
On Tue, Jul 14, 2009 at 1:48 PM, Ashley
Sheridan wrote:
> On Tue, 2009-07-14 at 13:41 -0300, Martin Scotta wrote:
>> He is calling the function by variable
>>
>> something like this
>>
>> $func = 'var_dump';
>>
>> $func( new Foo );
>>
>> On Tue, Jul 14, 2009 at 1:30 PM, Ashley
>> Sheridan wrote:
>>
On Tue, 2009-07-14 at 13:41 -0300, Martin Scotta wrote:
> He is calling the function by variable
>
> something like this
>
> $func = 'var_dump';
>
> $func( new Foo );
>
> On Tue, Jul 14, 2009 at 1:30 PM, Ashley
> Sheridan wrote:
> > On Tue, 2009-07-14 at 13:27 -0300, Martin Scotta wrote:
> >> $
He is calling the function by variable
something like this
$func = 'var_dump';
$func( new Foo );
On Tue, Jul 14, 2009 at 1:30 PM, Ashley
Sheridan wrote:
> On Tue, 2009-07-14 at 13:27 -0300, Martin Scotta wrote:
>> $immagine = $tipo($this->updir.$id.'.png');
>>
>> $tipo is undefined
>>
>>
>> On
On Tue, 2009-07-14 at 13:27 -0300, Martin Scotta wrote:
> $immagine = $tipo($this->updir.$id.'.png');
>
> $tipo is undefined
>
>
> On Tue, Jul 14, 2009 at 12:48 PM, Il pinguino
> volante wrote:
> > Hi to all
> >
> > I get a problem processing an image with GD libraries.
> >
> > This is my functi
$immagine = $tipo($this->updir.$id.'.png');
$tipo is undefined
On Tue, Jul 14, 2009 at 12:48 PM, Il pinguino
volante wrote:
> Hi to all
>
> I get a problem processing an image with GD libraries.
>
> This is my function
>
> public function showPicture($id) {
> header('Content-type: image/
Hi to all
I get a problem processing an image with GD libraries.
This is my function
public function showPicture($id) {
header('Content-type: image/jpeg');
$mime = mime_content_type($this->updir.$id.'.png');
$type = explode('/',$mime);
$type = 'imagecreatefrom'.$t
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