#x27;m lucky
>>
>>> that google is even finding my site!
>>>
>>> IN advance - I apologize for this off-topic question,
>>>
>> but this place is
>>
>>> a source of much knowledge, so I just threw in
>>>
>> a quick interlude here to
>>
>>> pick someone's brain. :)
>>>
>>>
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>>>
>>>
>>>
>> Yes - the sub is an add-on domain to my primary domain. Hence the
> overlap and problem.
>
>
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--
Willie Matthews
matthews.wil...@gmail.com
ngine for PHP.
> With PHP 5.4, it became even easier because somestuff()?> can be
> used without short_open_tag enabled.
> However, you always schould divide UI and backend.
>
> --- Ursprüngl. Mitteilung ---
> Von: Willie Matthews
> Gesend.: 25.04.2012, 23:48
> An: PHP M
to it? Also with the features of Smarty Template
Engine?
- --
Willie Matthews
matthews.wil...@gmail.com
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iQEcBAEBAgAGBQJPmHE9AAoJEPyaSMdprRSF+swH/jkXqfzG+uHE/g7Hle
Miles,
I never use auto increment. Not because of gaps, but in case I need to
reload the table. They do have meaning if they are foreign keys to another
table.
- Larry
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]]
Sent: Sunday, February 16, 2003 1:14 PM
To: Philli
Phillip,
You will have to change your code, so the primary key is not an auto
incremented value. If you don't, the auto increment will over-ride the 'get
next' function. Here is what I use in my code. You just need to change it
for your table.
//- GetNextKey -//
function getnextkey(){
ruary 15, 2003 11:01 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Re: SQL Query
The result recived from that query is this
ID SubID Interest Valid
Edit Delete 4 3 Star Craft 1
But I want a Query that retrives
"Star Craft", "Strategi", "Spel" and &qu
Zydox,
Please define 'sub-interest'. I've looked at what Uttam gave you, and it
looks correct, assuming you want want it limited to the same user. If you
result should be 'all with Interest = X and Valid = Y", just remove the
userid from the second query.
SELECT
InterestsList.ID, InterestsList.
id']) && isset($_POST['pword'])){
$_SESSION['user'] = $_POST['userid'];
$_SESSION['password'] = $_POST['pword'];
}
the if should be:
if ((statement)&&(statement))
{
}
so:
if ((isset($_POST['userid'])) && (iss
Tom,
I do have a session_start() in both files, but it does not seem to help.
- Larry
-Original Message-
From: Tom Rogers [mailto:[EMAIL PROTECTED]]
Sent: Sunday, January 12, 2003 11:36 AM
To: Willie G
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] SESSION variable to pass login ID
Hi
Hi,
I have been trying to solve the problem of using session variables, but I
have not had any luck. What I want to do is simple, I want to set my userid
and password in a login screen and use it later (in another php form) to log
into the database.
In my login PHP file I have the following:
if
RedHat 7.1 (Linux) has a package that converts from ASP
to PHP pages. I didn't use it, so I don't know if it
is useful neither if it is available for Windows.
Kind regards,
Willie
_
Seja avisado de novas mensagens do Hot
,
Willie D. Leiva
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Seja avisado de novas mensagens do Hotmail e use o comunique-se com seus
amigos com o MSN Messenger em http://messenger.msn.com.br
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