haliphax wrote:
On Mon, Mar 9, 2009 at 8:43 PM, Sashikanth Gurram wrote:
Is there any way in which I can assign a variable to a query string?
Like for example, Let us say that there are two php files a.php and
b.php. I am currently using a image tag like in a.php and am passing the value
Thanks Shawn and Dollah
-Sashi
Shawn McKenzie wrote:
Sashikanth Gurram wrote:
haliphax wrote:
On Mon, Mar 9, 2009 at 10:52 AM, Sashikanth Gurram
wrote:
haliphax wrote:
On Mon, Mar 9, 2009 at 10:24 AM, Sashikanth Gurram
wrote:
Nathan Nobbe
n Tue, Mar 10, 2009 at 8:14 AM, Sashikanth Gurram wrote:
Hello everyone,
Is there any way in which I can assign a variable to a query string?
Like for example, Let us say that there are two php files a.php and b.php. I
am currently using a image tag like in a.php and am passing the value to
haliphax wrote:
On Mon, Mar 9, 2009 at 10:52 AM, Sashikanth Gurram wrote:
haliphax wrote:
On Mon, Mar 9, 2009 at 10:24 AM, Sashikanth Gurram
wrote:
Nathan Nobbe wrote:
On Mon, Mar 9, 2009 at 7:32 AM, Sashikanth Gurram mailto:sashi...@vt.edu>> wrote:
Hi,
Thanks a lot everyone, particularly Haliphax, Nathan, Virgilio and Bob.
I will try it and will come back to you.
Thanks,
Sashi
haliphax wrote:
On Mon, Mar 9, 2009 at 10:24 AM, Sashikanth Gurram wrote:
Nathan Nobbe wrote:
On Mon, Mar 9, 2009 at 7:32 AM, Sashikanth Gurram
.
good luck,
-nathan
--
~
~~~~~~~~~
Sashikanth Gurram
Graduate Research Assistant
Department of Civil and Environmental Engineering
Virginia Tech
Blacksburg, VA 24060, USA
--
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ML tags to display your
image!), I definitely need the HTML tags, because this application works
based on the user input. So unless there is not input through a html
form, it wont work.
Thanks,
Sashi
On Mon, Mar 9, 2009 at 1:29 AM, Sashikanth Gurram wrote:
Hi Nathan,
Thanks a lot fo
_l mins\n
$location\n
\n";
}
echo "\n";
header('Content-Type: image/jpeg');
imagejpeg(imagecreatefromjpeg("$location"));
?>
Nathan Nobbe wrote:
On Sat, Mar 7, 2009 at 9:36 PM, Sashikanth Gurram wrote:
The thing is, I do not have a
ty_Spaces = $row[2];
$Distance = $row[3];
$time_l = $row[4];
$time_h=$row[5];
$location=$row[6]; echo "\n
$building\n
$parking_lot\n
$Number_of_Empty_Spaces\n
$Distance\n
$time_h - $time_l mins\n
$location\n
\n"
e, that is causing the image to be
displayed as binary. Is there any way we can convert the binary content
to jpeg/jpg content again. This is my guess after having gone through
the code again.\
Thanks,
Sashi
Nathan Nobbe wrote:
On Sat, Mar 7, 2009 at 8:12 PM, Sashikanth Gurram wrote:
I am just storing the location of the image(as a varchar type), not the
image itself. For example for a particular image, the location is stored
as C:\wamp\bin\apache\apache2.2.8\htdocs\Bldgs_lots\Burruss.jpg
-sashi
Nathan Nobbe wrote:
On Sat, Mar 7, 2009 at 7:10 PM, Sashikanth Gurram
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