sorry everyOne..
I have Found the answer..
Problem Solved..,
And Topic Canceled..
thanks..
Remon Redika writes:
Hi EveryOne..,
I need your help..
I am Using 2 Pages for Deleting rows..
In Page 1 Like This Below. (I am displaying The ID of table ..)
and my Page 1 Will Post to Page 2
in Page
Hi EveryOne..,
I need your help..
I am Using 2 Pages for Deleting rows..
In Page 1 Like This Below. (I am displaying The ID of table ..)
and my Page 1 Will Post to Page 2
in Page 2, I've Tried to Deleting Rows..
But I Can't Deleted the Rows... :(
PAGE 1
include "config.inc";
$mysqllang = "se
hi everyone..
i need delete two related table from mysql database,
but i am found and error..
this following my sql language :
DELETE FROM X INNER JOIN Y ON X.ID = Y.ID WHERE Y.No = 144;
i found an error in INNER JOIN syntax..
but i have successfully displaying 2 Related table in SELECT synta
I have put Image inside of my loop...
and that image located between and
I want the image not doing loop too. cause i just need one image..,
I just do looping for my data:
and
while ($row = mysql_fetch_array($myquery)){
?>
hi everyone,
It's Possible We used Php Scripting to Back the client Browser
Like This Below :
(ussualy I make it with java script) :
"javascript:history.back(1)"
but right now, i need using the 'header's function', functionaly to back
the page to previouse page.
sorry before :)
--
PHP Ge
hi everyone..
how to get the part of string and make it into a variable..
sample :
"determine"
now, i want to take just "mine" or 4 word from right, or "deter" (for left
function).
and after i got it, i want to make the "mine" into $x variable
my mind..
$x = "mean"
help please...
--
PHP
se not a good idea to translate my asp code to php??
sorry about my english
Rasmus Lerdorf writes:
Your code is bogus. You probably want:
$vary[$i] = $y;
And $vary(100) also makes no sense.
Also, why are you looping through the $InputY array and putting all the
values into $vary? Why
Parse error: parse error, unexpected '=' in
/home/intra/Inventroot/software/savedata.php on line 35
$vary(100);
$i = 0;
foreach($InputY as $y){
$vary($i) = $y; <-line 35
$i++;
}
foreach($Nama_Software as $x){
$insertq = "Insert into NSoftware (X, Y) values
('$In
I am Newbie in PHP
My Problem It's Too Hard to Explain but i'll try its..
I have Two Text Fields
The First Text Field i call it "InputX", the amount of InputX is Constant,
and The Second Text Field I Call it "InputY", Generatable Field
I have the Button usefull for Generated "InputY" (so If I C
which you would use request.form( ) for in
> ASP, use the $_POST
> array in PHP e.g. $var = $_POST{'var'}.
>
> Cheers!
>
> Scott
>
> On 10/2/2002 1:24 PM, Remon Redika wrote:
>> I am newbie in php
>> I have var $query_string in my address page.
>&
I am newbie in php
I have var $query_string in my address page.
I want get value of query string.
For example I give string on my query string like
www.mypages.com?var=numberx
I just want get a value of var or "numberx"
I usually do this var on asp
request.querystring("var") , so I'll get the val
i have tried to change post file from input.php3 to input.php
and it's done.
i wanna ask more .., why if i used post var to input.php3 the script doesn't
work. and i got message
Method Not Allowed
The requested method POST is not allowed for the URL /input.php3.
I just run two insert to do that.
with two different sql syntax ...
Chuck PUP Payne writes:
> Ok, Let's try this again, for some reason this didn't post from early today.
>
> I have db that has two tables that I am needing to post the same information
> into both tables, I can't use ID. S
gt;
>
> The "$index&1" construct will return either 0 or 1 for even and odd rows, so
> the proper color will be selected.
>
> HTH, Stas
>
> - Original Message -
> From: "Remon Redika" <[EMAIL PROTECTED]>
> To: <[EMAIL PRO
I wanna do with my bgcolor trough my array
">
blablabbaba
I have look my view source output my TR bgcolor , and i found this below
I want my bgcolor display with one by one like this below
etc
help please.
--
PHP General Mailing List (http://www.php.n
this is the form
-- insert.php
Nama Satu
Nama Dua
Nama Tiga
variable and my query --
$Namak = $namasa;
$Namak = $Namak.$namadu;
$Namak = $N
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