Curt Zirzow wrote:
or for the oneline purists :)
${ ${$this->fname} = $this->fname }();
wow.. ${} is more powerful than i had originally though.
Thank you Curt,
With your suggestion, I finally re-wrote the example, and here it is:
function foo() {
echo "In foo()\n";
}
class a {
var $fname;
Curt Zirzow wrote:
$this->{$this->fname}();
or (what it actually is doing.. )
$func = $this->fname;
$this->$func();
Curt
The point here is that the named function is outside the object. That
is, $this->foo() doesn't exist, so $this->{$this->fname}(), does not
work either.
But if you look
I need to record the names of functions, and then use them later.
Recently I found the following example within the on-line documentation:
\n";
}
$func = 'foo';
$func();// This calls foo()
?>
then I supposed that it was easy to extend this concept to objects and
wrote the following case:
Buff{0}) | ord($sBuff{1}) << 8 | ord($sBuff{2}) << 16
| ord($sBuff{3}) << 24;
// Get the numerical value of each byte, then shift the bytes to get the
4 byte number. (Little Endian)
Chris
Julio Sergio Santana wrote:
I'm just starting with PHP, and I've been browsing the wh
I tried the following and it didn't work:
X-Powered-By: PHP/4.1.2
Content-type: text/html
**
It was supposed to output:
***65***
[EMAIL PROTECTED] wrote:
http://us4.php.net/manual/en/function.base64-decode.php
-Original Message-
From: Julio Sergio Santana <[EMAIL PROTECTED]>
I'm just starting with PHP, and I've been browsing the whole manual to
find how to solve the following problem:
1. An integer number is internally represented in 4 bytes. Say, for
instance, number 65 is represented by 0x0041, that is the string
"\0\0\0\0x41", and not the string "65".
2. How
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