[PHP] Re: Problem with strtotime() and 2002-03-31

again, John "John Clarke" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > I have used the following script successfully for a year now, but have just > found a problem with the date 2002-03-31. > When I add 0 days t

[PHP] Problem with strtotime() and 2002-03-31

;2002-03-31","2"); echo $nd Regards John Clarke -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

Re: [PHP] year 2002 strtotime problem

lampén" <[EMAIL PROTECTED]> wrote in message 000401c1636f$fd37d960$ba93c5c3@Niklas">news:000401c1636f$fd37d960$ba93c5c3@Niklas... Great. :) I've got PHP 4.0.6 on linux. You? I think you should break the dates manually, it would be the most sure way to do it. Niklas -

Re: [PHP] year 2002 strtotime problem

1.""; > print $date2.""; > > print date("Y-m-d", strtotime($date1)).""; > print date("Y-m-d", strtotime($date2)).""; > ?> > > And the result was this: > " > Wed Dec 12 2001 > Sat Mar 1 2003 > 2001-12-12 &

[PHP] year 2002 strtotime problem

a 2nd time might cause this problem, as the first application was fine. I have tested all possible combinations of strtotime but the year 2002 always goes back to 2001 Have also tried just 'strtotime($date1)' but same problem again. Any help or comments would be greatly appreciated