How do I assemble strings to become a variable?
These code do not work...
$abc = 10;
echo $('ab'.'c');
$arr2 is a 2d array.
$arr1[0] = 1;
$arr1[1] = 10;
$arr2[0] = $arr1;
print $arr2[0][1];
Result will be 10
But,
$arr1[0] = 1;
$arr1[1] = 10;
$arr2[0] = $arr1;
$arr3 = each($arr2);
print $arr3[1];
Result is not 10. So, function "each" is not taking the whole $arr2[0]
out..
My question is wh
s file.
Any help is appreciated.
Jason Lam
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f the uploaded file.
Can anyone provide some hints as to how to properly handle these mac files?
Jason Lam
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I am wondering if there are any plans to fix the file upload performance problem.
Try uploading a 200M file by post to a PHP script, you'll notice how slow it is. Even
having enough RAM doesn't seems to help very much.
Jason Lam
mmended way? Or should I just re-compile everything? That will really
defeat the purpose of a packaging system
Jason Lam
local image (jpg) files over to client? I know how to stream it
the normal way, just don't know how I can stream it to some and not others.
Anyone have suggestions on this one?
Jason Lam
I got this strange problem, maybe a design flaw, please look at it and tell
me what's wrong.
3 files in total
1.php3
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--
2.php3
--
GO";
?>
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3.php3
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