I have been searching for this in the Zend docs and examples, but I don't
see it anywhere. In a PHP extension how do I access the elements of an
array that has been passed in?
Thanks,
Eric
"My mother's maiden name is not a password; my social security number is not
a PIN" - Kevin Mitnick
--
I think that was the first thing I tried.
It might have something to do with the actual image itself.
Images created with th PHP/GD routines come up with acceptable results.
Thanks,
Eric
Quoting Dan Lowe <[EMAIL PROTECTED]>:
> Previously, Eric Knudstrup said:
> > I am havin
I am having an issue with 4.0.5 where the following code snippet:
$orig = imagecreatefromjpeg($tmp);
echo 'orig x: ' . imagesx($orig) . ' orig y: ' . imagesy($orig)
. '';
$orig_size = getimagesize($tmp);
echo "orig x: $orig_size[0] orig y: $orig_si
Being new to PHP from the C world, is there anyway that I can enforce that
variables are declared for being used?
There have been a couple of times where I have been driven nuts trying to
find out why something isn't working and found that a variable name was off.
Eric
--
PHP General Mailing L
I'm looking for a PHP mode for XEmacs and really miss c-mode. Do you know
of any packages for it?
Eric
> -Original Message-
> From: Phillip Bow [mailto:[EMAIL PROTECTED]]
> Sent: Friday, March 30, 2001 7:18 AM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP] PHP Editor for Linux
>
>
> Read
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