Well the argument has both sides. Division by zero on many platforms resulted
in zero. Then came IBM360 and it generated an exception causing big time issues
in legacy code so a OS patch was written to intercept the interrupt, jam the
result to zero and return.
Although mathematically undefined
On Fri, May 27, 2011 at 11:52 PM, Arnold Hesnod wrote:
> Although I've been mostly using Java and Ruby in my professional software
> development work for the past decade or so, in the past two or three years
> I've started to do more and more PHP. I originally started using PHP
> because I neede
On Sat, May 28, 2011 at 1:34 PM, Andre Polykanine wrote:
> Hello Nathan,
>
> Do you mean $x{8}?
>
yup, that or $x[8];
> That is good but not for all situations.
> I need sometimes to make an array with letters as keys and numbers as
> values, like this (I give English alphabet just as an
Hello Nathan,
Do you mean $x{8}?
That is good but not for all situations.
I need sometimes to make an array with letters as keys and numbers as
values, like this (I give English alphabet just as an example, so
please don't suggest str_split):
$alphabet="abcdefghijklmnopqrstuvwxyz";
// I wish
Hello Peter,
It's not unicode... :-((
Yepp, I saw this thing in notes with array_map, array_chunk and
array_something_else but it's still too slow, on my opinion.
--
With best regards from Ukraine,
Andre
Skype: Francophile
My blog: http://oire.org/menelion (mostly in Russian)
Twitter: htt
Thanks Viraj,I'll read it.
Yes,you are right I visited the
http://stackoverflow.com/users/218196/felix-kling
and i found my problem and solved it
LOL :)
Just saw phpinfo() and you are right, it shows port 80 even if it's httpS :0
But the problem is, that $_SERVER['SERVER_PORT'] is apache variable and not
php, meaning that apache is telling PHP that it works on port 80.
Even if you use .htaccess and variable "%{SERVER_PORT}" it will not work
On Fri, 27 May 2011, Curtis Maurand wrote:
$_SERVER['HTTPS']
I don't see this at all.
I'm definitely connecting securely. Here are the status lines from Lynx
when surfing to https://MintFM.net/phpinfo.php:
1. Looking up mintfm.net
2. Making HTTPS connection to mintfm.net
3. Ve
On Sat, May 28, 2011 at 4:33 AM, Robert Cummings wrote:
> On 11-05-28 05:26 AM, Andre Polykanine wrote:
>
>> Hello Lester,
>>
>> Actually, many of the points are not important for me so far, however
>> this one really drives me mad:
>> http://phpsadness.com/?page=sad/35 (can't explode() by
hi nigen,
the intention of that 'exit' was to stop the script temporarily to
avoid any second time inserts. i think you better figure-out what
caused your script to insert same data twice in a single form post.
to hide the form, 'exit' is not the best option. there are several
different ways, one
On 28 May 2011 at 14:11, Igor Konforti wrote:
> It means that array $_POST does not have a key called "negin".
> Simple If statement before line 4 would fix this.
> On Sat, May 28, 2011 at 16:03, Negin Nickparsa wrote:
>> suppose that i have this SIMPLE code:
>> > echo"";
>> echo $_POST['negi
It means that array $_POST does not have a key called "negin".
Simple If statement before line 4 would fix this.
And I agree with @Jasper Mulder. Perhaps you should try
stackoverflow.comfor this kind of questions
Regards
On Sat, May 28, 2011 at 16:03, Negin Nickparsa wrote:
> I'm sorry tha
I'm sorry that I disturbed you and the List,I tried hard to mind my
punctuations but my English has weaknesses you can understand from my
posts,one time I apologized..
No my problem is not with these punctuations i know them
I said for example,I mean in general
suppose that i have this SIMPL
> Date: Sat, 28 May 2011 16:39:13 +0430
> From: nickpa...@gmail.com
> To: l...@mit-web.dk
> CC: php-general@lists.php.net
> Subject: Re: [PHP] how to use echo checkboxes in php when i don't have access
> to $_POST
>
> because when the name is in echo it ca
in this topic problem WAS this one:
insert to a table twice(that was solved)
and on that post problem is this one:
working with echo html then insert to a table (problem in $_POST)
I thought it is very different am i wrong?
cause it's in another topic!!! and another problem!
this problem was solved
i had another problem
what do you mean!?
because when the name is in echo it can't access to $_POST
4 example $_POST['p$i']
it tells me undefined variable p$i
when in html we write it in form because it has post method it can set
$_POST but here in php i just echo it and i can't access it
maybe i am wrong but how can i correct it?
But why do you double-post your question?
http://news.php.net/php.general/313198
?
On Sat, May 28, 2011 at 11:21, Negin Nickparsa wrote:
> i'm wondering that what was the problem!
> why with just a session it now works propely!!!
> how!
>
lør, 28 05 2011 kl. 13:32 +0430, skrev Negin Nickparsa:
> because I echo the checkboxes like this:
>
> if($num>0)
> {
> echo "";
> for($i=0;$i<$num;$i++)
> {
> $row=mysql_fetch_row($result);
> echo "";
> echo"";
> echo"$row[0]";
> echo"";
> }//for
> echo"";
> }//if
>
> i can't use $_POST because
On 11-05-28 05:26 AM, Andre Polykanine wrote:
Hello Lester,
Actually, many of the points are not important for me so far, however
this one really drives me mad:
http://phpsadness.com/?page=sad/35 (can't explode() by an empty
string)
Besides that, he says nothing about unicode issues.
I
On May 28, 2011 11:27 AM, "Andre Polykanine" wrote:
>
> Hello Lester,
>
> Actually, many of the points are not important for me so far, however
> this one really drives me mad:
> http://phpsadness.com/?page=sad/35 (can't explode() by an empty
> string)
http://www.php.net/manual/en/functio
Hello Lester,
Actually, many of the points are not important for me so far, however
this one really drives me mad:
http://phpsadness.com/?page=sad/35 (can't explode() by an empty
string)
Besides that, he says nothing about unicode issues.
I love PHP (I really do, it's a neat language,
i mean my tables in Mysql
because I echo the checkboxes like this:
if($num>0)
{
echo "";
for($i=0;$i<$num;$i++)
{
$row=mysql_fetch_row($result);
echo "";
echo"";
echo"$row[0]";
echo"";
}//for
echo"";
}//if
i can't use $_POST because it's not in html
how can i insert my items that are checked into table?
i'm wondering that what was the problem!
why with just a session it now works propely!!!
how!
Negin Nickparsa wrote:
I click the submit button just one time! not twice
but when i go to MySql and select * from it
it shows me happening two times
The code looks OK, so something is hitting it twice. I normally have a unique
index on anything that I do not want duplicates in - which would the
i used your exit too,yes it's better to hide the form after registration:)
Yes viraj it was in both tables
Hi viraj
intresting!
i changed the code to this:
$kind=$_SESSION['s3'];
$query1="insert into
user(kind,user,pass,name)values('$kind','$str','$str2','$str3')";
$result1=mysql_query($query1);
i set the session in my another page
and now it works properly:D
LOL!!
hi negin,
do you get duplicate inserts into both tables? if yes, try an
'exit();' right after the success message;
echo "you have been registered successfully!";
exit();
this will stop the script after the message, and you wont see the form
either. at this point check the tables for duplicate rec
I click the submit button just one time! not twice
but when i go to MySql and select * from it
it shows me happening two times
Consistently
here is the code:
Registration
Complete the form below:
Name:
Last name:
Username:
Password:
Negin Nickparsa wrote:
I have a code that i get the $_POST's result and then insert them in tables
of Mysql
it can run without error but it'll insert in the table twice and i don't
know why.
when I click the submit then with array_key_exists I go to if statement and
insert it.
i'll show the code
Daevid Vincent wrote:
A friend sent me this URL today. While amusing, he's got many valid points
and I certainly share in his frustration.
http://www.phpsadness.com
I'd take him a bit more seriously if he used a real name ;)
But many of the points I looked at simply reflect that he has yet to
I have a code that i get the $_POST's result and then insert them in tables
of Mysql
it can run without error but it'll insert in the table twice and i don't
know why.
when I click the submit then with array_key_exists I go to if statement and
insert it.
i'll show the code if someone have time help
Let me try and get back.
Thanks, Jasper!
On 28-May-2011, at 4:29 AM, Jasper Mulder
wrote:
From: shreya...@gmail.com
To: lord_fa...@hotmail.com
Subject: Re: [PHP] Urgent help - Token Generation code!
Date: Sat, 28 May 2011 04:15:59 +0530
Jasper,
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