On 2/23/2011 8:48 PM, Ron Piggott wrote:
Is there a way to make this syntax:
$checking_answer = $answer_reference_2;
Equal to:
$checking_answer = $answer_reference_ . ($i + 1);
(where $i = 1)
making $checking_answer take on the value of $answer_reference_2 ?
I am trying to develop a web ap
On 11-02-23 11:48 PM, Ron Piggott wrote:
Is there a way to make this syntax:
$checking_answer = $answer_reference_2;
Equal to:
$checking_answer = $answer_reference_ . ($i + 1);
(where $i = 1)
making $checking_answer take on the value of $answer_reference_2 ?
I am trying to develop a web ap
I must be missing something, why do you need to use variable variables when
checking user answers?
The logic should be something like:
$answer_key = array('question1' => 'answer', 'question2' => 'answer', );
foreach($answer_key as $q => $a)
{
check_answer($_POST[$q], $a);
}
Regards,
-
Is there a way to make this syntax:
$checking_answer = $answer_reference_2;
Equal to:
$checking_answer = $answer_reference_ . ($i + 1);
(where $i = 1)
making $checking_answer take on the value of $answer_reference_2 ?
I am trying to develop a web app quiz and I need to test the users answers
Hi.
> Wrong catch? [1]
>
> Regards,
> Tommy
No, it wasn't. If you look at where I pass in parameters, I have a
$parameter-> value bound as value of the parameter, which is wrong. It
should be just $parameter. I corrected my code (after digging for the
larger part of a week), and now it's working.
es
> >> >> either, but on my testing server on IE, it worked as I wanted but not
> >> >> on
> >> >> anything else. I chopped out most of the code and ended up with this:
> >> >>
> >> >> if ( isset($_POST['submit']) ) {} e
> so when
> you're using $_SERVER variables there's no call back to the server, as the
> code is still being run on the server at that point.
This is something I actually do understand. I was wondering if the
code running on the server had to query the server for the information
every time a $_S
ither, but on my testing server on IE, it worked as I wanted but not
>> >> on
>> >> anything else. I chopped out most of the code and ended up with this:
>> >>
>> >> if ( isset($_POST['submit']) ) {} else {
>> >> pri
ything else. I chopped out most of the code and ended up with this:
> >>
> >> if ( isset($_POST['submit']) ) {} else {
> >> print "\n";
> >> if ($Recordset1) {
> >> print "\n";
> >> print " \n";
> >> pri
> $_SERVER is just a prepopulated superglobal array that is created at
> runtime.
Thanks for the clear answer.
Marc
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On Wed, Feb 23, 2011 at 14:00, Marc Guay wrote:
> This question will probably reveal my lacking knowledge of the
> fundamentals, but I'm a go for it anyway:
>
> When you use a $_SERVER variable, is a query made to the server to get
> the information or is it just sitting in a variable all ready to
e \n"; //2 fields in Counties table, State and
>> County
>> print " County \n";
>> print "\n";
>> //create table
>> $i = 0;
>> while ( $row = mysql_fetch_array($Recordset1) ) {
>> $i++;
>> print "\n";
>> print &q
Marc,
$_SERVER is an array and it should have all the information. I do not know
the answer for the latter part of your query.
Regards,
Shreyas
On Thu, Feb 24, 2011 at 12:30 AM, Marc Guay wrote:
> This question will probably reveal my lacking knowledge of the
> fundamentals, but I'm a go for i
This question will probably reveal my lacking knowledge of the
fundamentals, but I'm a go for it anyway:
When you use a $_SERVER variable, is a query made to the server to get
the information or is it just sitting in a variable all ready to go?
Reworded, is there any efficiency gained by storing t
e \n"; //2 fields in Counties table, State and
>> County
>> print " County \n";
>> print "\n";
>> //create table
>> $i = 0;
>> while ( $row = mysql_fetch_array($Recordset1) ) {
>> $i++;
>> print "\n";
>> print &q
On Tue, Feb 22, 2011 at 19:03, Paul M Foster wrote:
> Not a bad idea for HTML, not so great for PHP. Some of what you're
> trying to solve/avoid can be handled by a decent editor, one that does
> syntax highlighting and/or does brace and parenthesis checking. It
> doesn't require an expensive IDE.
;; //2 fields in Counties table, State and County
> print " County \n";
> print "\n";
> //create table
> $i = 0;
> while ( $row = mysql_fetch_array($Recordset1) ) {
> $i++;
> print "\n";
> print " value=\"$row[name]\">\n
On Feb 22, 2011, at 5:29 AM, Dotan Cohen wrote:
I wrote a short page on how to actually type of code that one writes,
it can be found here:
http://dotancohen.com/howto/write_code.html
The point that I stress on the page is that first you close an
element, then you fill it's contents. The page
x27;state_id']}\n";
echo "{$row['name']}\n";
echo "\n";
}//end while
print "\n";
} else {
echo("Error performing query: " .
mysql_error() . "");
}
print "\n";
print "\n";
}
?>
Again, thank you.
Gary
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This bit?
On 22/02/11 22:06, Gary wrote:
for($i=1; $i<=$_POST['counties']; $i++) {
if ( isset($_POST["county{$i}"] ) ) {
You loop over $_POST['counties'] and look for $_POST["county$i"]
I suspect that there is no field 'counties' in your form, so the server is
complaining about the missing i
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