Well if anyone cares to know what this problem was. We have no idea. We
duplicated the sites templates, docroot, site is still using same shared
plugins it was before, javascript, etc...
The only thing that is different is that it is on a new doc root and new
subdomain,
members2.myhomegrown.com i
>From my experience, I'd have to say that it would be a real tough go
to crack that. If there was a weak point in the scheme is that your
end result pattern ( the ssn ) is defined with a pair of constants,
the hyphens. In our scheme we remove the dashes and just provide a
mask for display. We also
On Aug 11, 2010, at 6:50 PM, tedd wrote:
> Hi gang:
>
> Okay, a question to the Encryption/Decryption gurus out there.
>
> If you were given:
>
> 1. This encrypted string:
>
> p3IVhDBT26i+p4vd7J4fAw==
>
> 2. Were told it was a social security number (i.e., in the form of
> 123-45-6789).
>
>
Hi gang:
Okay, a question to the Encryption/Decryption gurus out there.
If you were given:
1. This encrypted string:
p3IVhDBT26i+p4vd7J4fAw==
2. Were told it was a social security number (i.e., in the form of
123-45-6789).
3. And it had been generated from this code:
$cipher = mcrypt_modu
On Thu, 2010-08-12 at 02:02 +0430, Ali Asghar Toraby Parizy wrote:
> Hi.
> I need a protected directory in my server that only the authenticated user
> can reach all files in that folder(file type is zip and picture or a web
> page, maybe). I save user ID and passwords in mysql database. today I t
Hi.
I need a protected directory in my server that only the authenticated user
can reach all files in that folder(file type is zip and picture or a web
page, maybe). I save user ID and passwords in mysql database. today I tried
to use htaccess but mod_auth_mysql isn't installed on my server.
I know
On 11 August 2010 13:58, Bob McConnell wrote:
> From: Richard Quadling
>
>> Quick set of eyes needed to see what I've done wrong...
>>
>> The following is a reduced example ...
>>
>> > $Set = array();
>> $Entry = 'Set[1]';
> ^^
> Shouldn't that be $Set[1]?
>
>> $Value = 'Assigned';
From: Richard Quadling
> Quick set of eyes needed to see what I've done wrong...
>
> The following is a reduced example ...
>
> $Set = array();
> $Entry = 'Set[1]';
^^
Shouldn't that be $Set[1]?
> $Value = 'Assigned';
> $$Entry = $Value;
> print_r($Set);
> ?>
Bob McConnell
--
On 10 August 2010 18:08, Andrew Ballard wrote:
> On Tue, Aug 10, 2010 at 12:23 PM, Richard Quadling
> wrote:
>> On 10 August 2010 16:49, Jim Lucas wrote:
>>> Richard Quadling wrote:
Hi.
Quick set of eyes needed to see what I've done wrong...
The following is a redu
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