Worst than that :) In theory I can refactor the super code and commit,
but SmalltalkHub does not let me commit even I have RW access... So I
have to knock at the Philippe's or Masashi's door so they can commit it
for me. It's annoying to bother busy people. Anyway enough small talk ;)
Le 21/01/201
yes, something like factoring out in its own method a chunk of code in
super super method I want to access from my subclass.
Le 21/01/2017 à 19:32, Sebastian Heidbrink via Pharo-users a écrit :
> Now I am wondering what you guys are meaning by "hooks"?
--
Dr. Geo
http://drgeo.eu
--- Begin Message ---
Hi Hilaire,
I had this once, too. No time to refactor or rethink my subclass structure.
Now I am wondering what you guys are meaning by "hooks"?
Something like this? A ClassExtension?
SuperSuperClass
- methodIWantToReach
- myExtendedMethod
^self methodIWan
Out of curiosity, wouldn't it be better to temporarily duplicate the code in
your class and talk with the upstream owner? (That would be my usual approach.)
Peter
On Sat, Jan 21, 2017 at 06:04:12PM +0100, Hilaire wrote:
> Agree on the hook. However the super class are not mine. Not an ideal
> s
Yep, it is the first situation I face where I need it in 10 years of
Smalltalk/Pharo. Otherwise I will refactor super class package, may be I
should
Le 21/01/2017 à 11:19, stepharong a écrit :
> pay attention and to not use it. It is evil to use that in plain domain
> code.
--
Dr. Geo
http://drg
Agree on the hook. However the super class are not mine. Not an ideal
situation
Le 21/01/2017 à 11:19, stepharong a écrit :
> No and I'm happy that this is like that.
> I think that it means that you need to create special hooks in the super
> superclass.
--
Dr. Geo
http://drgeo.eu
Thanks Henrik
Le 15/01/2017 à 22:33, Henrik Nergaard a écrit :
> menu perform: #isMorph withArguments: #() inSuperclass: ProtoObject. "Error
> #isMorph not implemented"
--
Dr. Geo
http://drgeo.eu
#perform:withArugments:inSuperclass:
| menu |
menu := MenuMorph new.
menu isMorph. "true"
menu perform: #isMorph withArguments: #() inSuperclass: Morph. "true"
menu perform: #isMorph withArguments: #() inSuperclass: Object."false"
menu perform: #isMorph withArguments: #() inSuperclass: ProtoObjec
You should be able to call super super, as high up as you need to go. At least
you can in VA Smalltalk.
Brad Selfridge
913-269-2385
> On Jan 15, 2017, at 3:42 PM, Hilaire wrote:
>
> Hi,
>
> Is there a way from an instance to access a method situated 2 layers up
> in the class hierarchy?
>
>
