On 2018-Sep-05, Tom Lane wrote:
> Alvaro Herrera writes:
> > That said, I haven't heard of anyone using these functions in code yet,
> > so if we change it in 11 or 12 nobody is going to complain.
>
> ... and that's pretty much my feeling. It seems really unlikely that
> anyone's using named-a
Alvaro Herrera writes:
> On 2018-Sep-03, Tom Lane wrote:
>> I do not think we can change the names of the output arguments;
>> it'd break existing queries. However, renaming input arguments
>> shouldn't affect anything. So I propose we make pg_get_object_address'
>> input arguments be named type
On 2018-Sep-03, Tom Lane wrote:
> Jean-Pierre Pelletier writes:
> > Two of the out arguments name of function
> > "pg_identify_object_as_address" are not as documented.
> > Documentation says "name" and "args", but function returns
> > "object_names" and "object_args".
>
> Hm, yeah. The documen
Andrew Gierth writes:
> "Tom" == Tom Lane writes:
> Tom> I do not think we can change the names of the output arguments;
> Tom> it'd break existing queries. However, renaming input arguments
> Tom> shouldn't affect anything.
> What about callers that might be using named-argument notation?
O
> "Tom" == Tom Lane writes:
Tom> I do not think we can change the names of the output arguments;
Tom> it'd break existing queries. However, renaming input arguments
Tom> shouldn't affect anything.
What about callers that might be using named-argument notation?
--
Andrew (irc:RhodiumToad
Jean-Pierre Pelletier writes:
> Two of the out arguments name of function
> "pg_identify_object_as_address" are not as documented.
> Documentation says "name" and "args", but function returns
> "object_names" and "object_args".
Hm, yeah. The documentation of pg_get_object_address() seems
equally
Two of the out arguments name of function
"pg_identify_object_as_address" are not as documented.
Documentation says "name" and "args", but function returns
"object_names" and "object_args".
This query shows what the function returns:
select (pg_identify_object_as_address(classId, ObjId, objSubId))