On Tue, May 25, 2021 at 10:23 PM Tom Lane wrote:
> David Rowley writes:
> > On Tue, 25 May 2021 at 22:28, Andy Fan wrote:
> >> explain (costs off) select (select count(*) filter (where t2.b = 1)
> from m1 t1)
> >> from m1 t2 where t2.b % 2 = 1;
> >>
> >> This one is too confusing to me since t
David Rowley writes:
> On Tue, 25 May 2021 at 22:28, Andy Fan wrote:
>> explain (costs off) select (select count(*) filter (where t2.b = 1) from m1
>> t1)
>> from m1 t2 where t2.b % 2 = 1;
>>
>> This one is too confusing to me since the Aggregate happens
>> on t2 rather than t1. What happens
On Tue, May 25, 2021 at 7:42 PM David Rowley wrote:
> On Tue, 25 May 2021 at 22:28, Andy Fan wrote:
> >
> > explain (costs off) select (select count(*) filter (where t2.b = 1)
> from m1 t1)
> > from m1 t2 where t2.b % 2 = 1;
> >
> > QUERY PLAN
> > ---
> >
On Tue, 25 May 2021 at 22:28, Andy Fan wrote:
>
> explain (costs off) select (select count(*) filter (where t2.b = 1) from m1
> t1)
> from m1 t2 where t2.b % 2 = 1;
>
> QUERY PLAN
> ---
> Aggregate
>-> Seq Scan on m1 t2
> Filter: ((b % 2) = 1)
My question can be demonstrated with the below example:
create table m1(a int, b int);
explain (costs off) select (select count(*) filter (*where true*) from m1
t1)
from m1 t2 where t2.b % 2 = 1;
QUERY PLAN
-
Seq Scan on m1 t2
Filter: ((b % 2) = 1)