"David Johnston" writes:
> The expression:
> (some_composite).calculated_field
> resolves to the function call:
> calculated_field(some_composite)
> I know I've seen it before, though whether in the docs or in e-mail I am
> unsure, but for the life of me browsing for it for about 10 minutes got m
On Mon, Aug 27, 2012 at 3:46 PM, David Johnston wrote:
> With Chris Travers recently going O-R gung-ho on us I decided I wanted to
> find out where in the documentation the following behavior is specified:
>
> The expression:
>
> (some_composite).calculated_field
>
> resolves to the function call:
