By George, I think you've got it!
(Imagine a hokey imitation British accent.)
I only had to make one small change. It complained it didn't know about a
column named "charge". When I changed it to:
select charge, (cn).* from (select charge, chargeneeds(charge) as cn from
charge) q;
it worke
On Thu, Jun 4, 2009 at 4:40 PM, Radcon Entec wrote:
> Merlin,
>
> Thank you for your reply. Unfortunately, I was not able to get it to work.
> The SQL statements you gave me generated syntax errors.
>
> I tried to follow your thoughts, though. I created the following type:
>
> CREATE TYPE charge
On Thu, Jun 4, 2009 at 11:15 AM, Radcon Entec wrote:
> Greetings!
>
> Having received the answer I needed to my question about using functions
> with OUT parameters from this list (thanks very much!), I find myself
> confused about how to use the function in a view. The function chargeneeds
> tak
Greetings!
Having received the answer I needed to my question about using functions with
OUT parameters from this list (thanks very much!), I find myself confused about
how to use the function in a view. The function chargeneeds takes one input
parameter, a charge number, and has 3 output para
