Or you could use:
SELECT name
FROM templates
WHERE name ~ '\_cont\_';
This does it as a regular expression.
~* '\_aa\_';
On Fri, Oct 24, 2008 at 5:07 PM, Craig Ringer
<[EMAIL PROTECTED]> wrote:
> Alan Hodgson wrote:
>> On Friday 24 October 2008, "Gauthier, Dave" <[EMAIL PROTECTED]> wrote:
>>> I
Alan Hodgson wrote:
> On Friday 24 October 2008, "Gauthier, Dave" <[EMAIL PROTECTED]> wrote:
>> I read in the docs (section 9.7.1) that the backslash... \ ... is the
>> default escape char to use in "like" expressions. Yet when I try it, it
>> doesn't seem to work the ay I expect. Here's an examp
On Friday 24 October 2008, "Gauthier, Dave" <[EMAIL PROTECTED]> wrote:
> I read in the docs (section 9.7.1) that the backslash... \ ... is the
> default escape char to use in "like" expressions. Yet when I try it, it
> doesn't seem to work the ay I expect. Here's an example...
>
> select name fro
On Fri, Oct 24, 2008 at 08:12:38AM -0700, Gauthier, Dave wrote:
> select name from templates where name like '%\_cont\_%';
>
> name
> --
> cgidvcontrol
> x8idvcontrol
> etc
>
> I would expect to NOT see these because the "cont" is not preceded by
> an
I read in the docs (section 9.7.1) that the backslash... \ ... is the default
escape char to use in "like" expressions. Yet when I try it, it doesn't seem
to work the ay I expect. Here's an example...
select name from templates where name like '%\_cont\_%';
name
