7.4.2 gives it like this:
testbed=# select replace('test %%400%% result',
'result', 'ok');
replace
-
test %%400%% ok
(1 row)
testbed =# select replace('test %400% result',
'result', 'ok');
replace
---
test %400% ok
(1 row)
Ted
-- Nicolas Bottar
Stephan Szabo <[EMAIL PROTECTED]> writes:
> On Tue, 13 Jul 2004, Nicolas Bottarini wrote:
>> In postgreSQL 7.3.2 when I execute the following query
>>
>> select replace('test %400% result', 'result', 'ok');
>>
>> it returns "test % ok"
> I think this was fixed in the 7.4 branch.
It was fixed in
On Tue, 13 Jul 2004, Nicolas Bottarini wrote:
> In postgreSQL 7.3.2 when I execute the following query
>
> select replace('test %400% result', 'result', 'ok');
>
> it returns "test % ok"
I think this was fixed in the 7.4 branch.
---(end of broadcast)-
In postgreSQL 7.3.2 when I execute the following query
select replace('test %400% result', 'result', 'ok');
it returns “test % ok”
And If I Execute:
select replace('test %%400%% result', 'result', 'ok');
it returns the correct result: “test %400% ok”
If this is a known BUG pl
