Re: user-defined operators?

On Thu, 24 Jun 2004 10:55:26 -0700, Larry Wall <[EMAIL PROTECTED]> wrote: Well, any operator or function that knows how to call a closure can function as a short-circuit operator. The built-in short-circuit operators are a bit special insofar as they're a kind of macro that treats the right side

if, loop, and lexical scope

AFAIR, I've seen in some Apocalypse that lexical scope boundaries will be the same as boundaries of block, in which lexical variable was defined. so, my question is, what the scope of variables, defined in C and C conditions? in perl5: my $a="first\n"; if (my $a="second\n") {print $a}

Re: user-defined operators?

Alexey Trofimenko writes: > On Thu, 24 Jun 2004 10:55:26 -0700, Larry Wall <[EMAIL PROTECTED]> wrote: > > > >Well, any operator or function that knows how to call a closure can > >function as a short-circuit operator. The built-in short-circuit > >operators are a bit special insofar as they're a

Re: if, loop, and lexical scope

Alexey Trofimenko writes: > AFAIR, I've seen in some Apocalypse that lexical scope boundaries will be > the same as boundaries of block, in which lexical variable was defined. Yep. Except in the case of routine parameters, but that's nothing new. > > so, my question is, what the scope of var