Darren Duncan wrote:
I think that it would be better to pick the other meaning of C<^4>
instead, meaning C<0..3>, because that keeps the meaning of "^"
consistent as "up to but not including". Then also saying ^4 means you
get a range of 4 elements, so there is that consistency too.
Also, th
pugs-comm...@feather.perl6.nl wrote:
Author: moritz
Date: 2009-09-13 19:42:10 +0200 (Sun, 13 Sep 2009)
New Revision: 28233
Modified:
docs/Perl6/Spec/S03-operators.pod
Log:
[S03] ^4 cannot mean 0..3 and 0..^4 at the same time, because they are not the
same
The unary C<^> operator generates
