Brad Bowman wrote:
my $a = rand(); # runtime variable
my $result = one(any( sub { $a+1}, sub { $a-1} ),sub { $a+3 }).();
say $result.perl;
If $a was 0.5 I'd guess
$result = one(any(1.5, 0.5), 3.5)
is this the case?
IIRC the .perl method produces a string from which an equal value
can be re
Once more, with less room to wriggle...
> > I'd guess the rule is "call 'em all and return a similarly
> > structured junction". How far off the mark am I?
>
> Unless you ask a question nothing is called.
Boolean context is clear, how about scalar:
my $a = rand(); # runtime variable
my $
Brad Bowman wrote:
Assuming this is allowed, what will the .() calls below return?
Does the result depend on the calling context?
...
one(any(@subs),sub { ... }).();
Starting to argument from the statement that junctions are values
the above plays in the league of 3.() which might not have observe
