David Whipp:
# Brent Dax wrote:
# > $href = hash { %hash }; #B
#
# Why the curlies? if C is a function (ctor), then surely
# these should be parentheses. In this context, parentheses are
# optional, so this could be written
#
#$href = hash %hash;
C is not a function. It's a keyword
Brent Dax wrote:
> $href = hash { %hash }; #B
Why the curlies? if C is a function (ctor), then surely these should
be parentheses. In this context, parentheses are optional, so this could be
written
$href = hash %hash;
Dave.
On Monday 15 July 2002 11:22 pm, Deborah Ariel Pickett wrote:
> Besides, does
> $hashref = some_function_returning_a_hash()
> make $hashref simply refer to the result of the function, or does it
> make $hashref refer to a hash containing a *copy* of the result of the
> function? If Perl6 is
Deborah Ariel Pickett:
# > > ..., and someone pointed out that it had a problem
# > > with code like "{ some_function_returning_a_hash()
# }". Should it give a
# > > closure? Or a hash ref? ...
# > Oh, well now that it's stated this way... (something went
# wrong in my
# > brain wh
Back to this again . .
> > ..., and someone pointed out that it had a problem
> > with code like "{ some_function_returning_a_hash() }". Should it give a
> > closure? Or a hash ref? ...
> Oh, well now that it's stated this way... (something went wrong in my
> brain when I read the
> ..., and someone pointed out that it had a problem
> with code like "{ some_function_returning_a_hash() }". Should it give a
> closure? Or a hash ref? ...
Oh, well now that it's stated this way... (something went wrong in my
brain when I read the actual message) It returns a clos
