Re: not a reference - What does this mean?

2008-05-04 Thread Jonathan Worthington
John M. Dlugosz wrote: Perl 6 doesn't have references anymore, it has captures. So, what does the following mean: @x = ; $a = [1, 2, [EMAIL PROTECTED]; I imagine that the 3rd element of the Array is itself an Array, and is the same object that is bound to @x. But captures are lazy context-

not a reference - What does this mean?

2008-05-04 Thread John M. Dlugosz
Perl 6 doesn't have references anymore, it has captures. So, what does the following mean: @x = ; $a = [1, 2, [EMAIL PROTECTED]; I imagine that the 3rd element of the Array is itself an Array, and is the same object that is bound to @x. But captures are lazy context-sensitive beasts, so I w

Where is "Manhattan Dispatch" discussion?

2008-05-04 Thread John M. Dlugosz
I want to review and collect the wisdom of what has been discussed before. Someone mentioned this the other day, as being a significant consensus. But I can't find anything in the forum archives. Can someone point to the discussion, position papers, etc.? --John

Re: grammar for 'constant' ?

2008-05-04 Thread John M. Dlugosz
Moritz Lenz moritz-at-casella.verplant.org |Perl 6| wrote: Then in S12 it shows my constant ... and our constant ... that is, independant from the my or our declarator. I grep'ped STD.pm tentatively for other occurrences of 'constant', and couldn't find where that should be imple

Re: grammar for 'constant' ?

2008-05-04 Thread Moritz Lenz
John M. Dlugosz wrote: > The synopses are contradictary over the way 'constant' works. First it says > that it is a declarator like 'my'. That's what STD.pm says: token scope_declarator:my { {*} } token scope_declarator:our { {*} } token scope_declarator:state{ {*} } token