Chas Owens wrote:
Jonathan Lang wrote:
> Is there any reason why we can't simply define '$a x $n' as being
> shorthand for 'cat($a xx $n)'? In what way does the former differ
> from the latter, other than the use of a Whatever in place of $n?
"$a x $n" is equivalent to "join '', $a xx $n", but
On 6/2/07, Jonathan Lang <[EMAIL PROTECTED]> wrote:
Is there any reason why we can't simply define '$a x $n' as being
shorthand for 'cat($a xx $n)'? In what way does the former differ
from the latter, other than the use of a Whatever in place of $n?
--
Jonathan "Dataweaver" Lang
"$a x $n" is
Is there any reason why we can't simply define '$a x $n' as being
shorthand for 'cat($a xx $n)'? In what way does the former differ
from the latter, other than the use of a Whatever in place of $n?
--
Jonathan "Dataweaver" Lang
Author: larry
Date: Sat Jun 2 14:45:43 2007
New Revision: 14414
Modified:
doc/trunk/design/syn/S03.pod
Log:
First installment of filling out descriptions of operator semantics.
Modified: doc/trunk/design/syn/S03.pod
===
Author: larry
Date: Sat Jun 2 12:42:11 2007
New Revision: 14413
Modified:
doc/trunk/design/syn/S02.pod
doc/trunk/design/syn/S03.pod
doc/trunk/design/syn/S04.pod
doc/trunk/design/syn/S06.pod
doc/trunk/design/syn/S09.pod
doc/trunk/design/syn/S13.pod
Log:
Dropped : from all listop
