Hello everyone,
This is my first post to the actual mailing list and not to Google Groups
(yeah, took me a bit to figure out they're not the same). I have a few
questions about the rules in Perl 6, and hopefully I'm not repeating stuff
that's already been brought up before. (I searched through the
Luke Palmer skribis 2006-02-13 9:46 (+):
> class Baz {
> does Foo;
> does Bar; # does this count as double declaration?
> }
I'd put composition and inheritance in a slightly different category
than accessor *generators*.
Juerd
--
http://convolution.nl/maak_juerd_bl
On 2/13/06, Juerd <[EMAIL PROTECTED]> wrote:
> Luke Palmer skribis 2006-02-13 9:36 (+):
> > That's a compile time error. Both "has" declarations generate a
> > method "a", so it is a method conflict.
>
> Doesn't normally double declaration end in the later masking/overriding
> the earlier dec
On 2/13/06, Amos Robinson <[EMAIL PROTECTED]> wrote:
> I think there's a typo in synopsis 5, "Indirectly quantified subpattern
> captures:"
> [ (\w+) \: (\w+ \h+)* \n ]**{2...}
> I have a feeling the \h should be *, not +.
It looks like you're right. Thanks, fixed.
Luke
Luke Palmer skribis 2006-02-13 9:36 (+):
> That's a compile time error. Both "has" declarations generate a
> method "a", so it is a method conflict.
Doesn't normally double declaration end in the later masking/overriding
the earlier declaration, with a warning, but not an error?
I'd expect
On 2/13/06, Yiyi Hu <[EMAIL PROTECTED]> wrote:
> For perl 6,
> Array and Scalar are in different namespace.
> So,
> class A { has $.a; has @.a };
>
> what will A.new.a return by default?
That's a compile time error. Both "has" declarations generate a
method "a", so it is a method conflict.
Luke
