On Thu, Aug 25, 2005 at 09:25:30PM -0400, Matt Fowles wrote:
> I have a simple question. Who comprises @Larry? I am fairly sure
> that I know a few people in it, but I am highly doubtful that I know
> all of them.
dev.perl.org has a "Who's Who" list:
http://dev.perl.org/perl6/people.html
T
> "MF" == Matt Fowles <[EMAIL PROTECTED]> writes:
MF> All~
MF> I have a simple question. Who comprises @Larry? I am fairly sure
MF> that I know a few people in it, but I am highly doubtful that I know
MF> all of them.
if $you_have_to_ask ~~ @Larry {
say 'you are not in @Larr
All~
I have a simple question. Who comprises @Larry? I am fairly sure
that I know a few people in it, but I am highly doubtful that I know
all of them.
Thanks,
Matt
--
"Computer Science is merely the post-Turing Decline of Formal Systems Theory."
-Stan Kelly-Bootle, The Devil's DP Dictionary
On 8/25/05, Yuval Kogman <[EMAIL PROTECTED]> wrote:
> On Thu, Aug 25, 2005 at 11:16:56 -, David Formosa (aka ? the Platypus)
> wrote:
> > On Wed, 24 Aug 2005 16:13:03 +0300, Yuval Kogman <[EMAIL PROTECTED]> wrote:
> >
> > [...]
> >
> > > perl6 creates a new instance of the perl compiler (presu
Hi,
with PIL-Run (Perl 6 to Perl 5 compiler) progressing rapidly, the topic
"binding" came up on #perl6.
"Binding is a simple symbol table manipulation, right?"
"No, consider @array[$idx] := $var or more generally
$sub(@args) := $var."
Then we wondered what should happen to array elements
Hi,
Yuval Kogman wrote:
> On Thu, Aug 25, 2005 at 15:42:28 +0200, Ingo Blechschmidt wrote:
>> This section will contain all information needed:
>> * User-defined operators
>> * Other symbols exported by "is export"
>> * Exported macros
>
> Okay, this raises a distinction:
>
> Compile time export
On Thu, Aug 25, 2005 at 15:42:28 +0200, Ingo Blechschmidt wrote:
> This section will contain all information needed:
> * User-defined operators
> * Other symbols exported by "is export"
> * Exported macros
Okay, this raises a distinction:
Compile time exports
Runtime exports
Modu
Hi,
Yuval Kogman wrote:
> On Thu, Aug 25, 2005 at 11:16:56 -, David Formosa (aka ? the
> Platypus) wrote:
>> On Wed, 24 Aug 2005 16:13:03 +0300, Yuval Kogman
>> <[EMAIL PROTECTED]> wrote:
>> > perl6 creates a new instance of the perl compiler (presumably an
>> > object). The compiler will only
On Aug 25, 2005, at 7:16 AM, David Formosa (aka ? the Platypus) wrote:
On Wed, 24 Aug 2005 16:13:03 +0300, Yuval Kogman
<[EMAIL PROTECTED]> wrote:
[...]
perl6 creates a new instance of the perl compiler (presumably an
object). The compiler will only compile the actual file 'foo.pl',
and d
On Thu, Aug 25, 2005 at 11:16:56 -, David Formosa (aka ? the Platypus)
wrote:
> On Wed, 24 Aug 2005 16:13:03 +0300, Yuval Kogman <[EMAIL PROTECTED]> wrote:
>
> [...]
>
> > perl6 creates a new instance of the perl compiler (presumably an
> > object). The compiler will only compile the actual
On Wed, 24 Aug 2005 16:13:03 +0300, Yuval Kogman <[EMAIL PROTECTED]> wrote:
[...]
> perl6 creates a new instance of the perl compiler (presumably an
> object). The compiler will only compile the actual file 'foo.pl',
> and disregard any 'require', 'use', or 'eval' statements.
use has the potenti
On Thu, Aug 25, 2005 at 20:23:55 +1000, Stuart Cook wrote:
> Here's a suggestion:
> Within argument lists, both of them are special syntactic forms for
> named arguments:
>
> foo(a => 'b', :c); # both named args
> my $pair = :a;
> foo($pair); # not a named-arg call
> ...or else find new
Here's a suggestion:
Outside of argument lists, both a=>'b' and :a('b') (and friends) are
equivalent, and denote an ordinary pair value.
Within argument lists, both of them are special syntactic forms for
named arguments:
foo(a => 'b', :c); # both named args
If you want to pass pair values i
On 8/24/05, Damian Conway <[EMAIL PROTECTED]> wrote:
> Larry wrote:
>
> > Plus I still think it's a really bad idea to allow intermixing of
> > positionals and named. We could allow named at the beginning or end
> > but still keep a constraint that all positionals must occur together
> > in one z
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