Leopold Toetsch <[EMAIL PROTECTED]> writes:
> Piers Cawley wrote:
>> But under this scheme, the implementing function will have to do a
>> saveall for every function it calls because it doesn't know what
>> registers its caller cares about. And you're almost certainly going
>> to want to call othe
# New Ticket Created by Jens Rieks
# Please include the string: [perl #29994]
# in the subject line of all future correspondence about this issue.
# http://rt.perl.org:80/rt3/Ticket/Display.html?id=29994 >
% cat error.imc
.sub _main @MAIN
.local string na123me
na123me = "/foo"
lo
On Sat, 2004-05-29 at 15:29, Dan Sugalski wrote:
> The problem with the first scheme is that anything that has a handle
> on the PMC will not get the new layers. Not a good thing.
I like the first scheme. The question that comes up is: when does
something get layered?
That is: if I have code th
Okay, since I was asked, and I'm starting to hit a need for it in
general, I want to address morph, and some of its ramifications. And
limitations, as it seems like it's only a partial solution
We had issues way back about this and we worked 'em out, at least to
some extent. Now that I'm diggin
I thought I had already replied to this but I don't
seem to see it in the archive anywhere.
--- Leopold Toetsch <[EMAIL PROTECTED]> wrote:
> I think next step would need to review Cygwin math
> lib sources and trace
> into the library. Nasty.
Parrot doesn't use GMP right? So the math library in
Dan Sugalski <[EMAIL PROTECTED]> wrote:
> If you want to go back to a frame pointer style of register stack
> access, that's doable, but that's the way it was in the beginning and
> the performance penalties in normal code outweighed the savings in
> stack pushes.
JITted memory access through the
Joshua Gatcomb <[EMAIL PROTECTED]> wrote:
> Well, it only happens under JIT for the following
> functions (identical code for atan works fine):
> cosh, sinh, tanh, sech, exp, pow
> It only happens if there are two set N# prior to the
> function where # is two different numbers
> N0 = 1
> N1 = 1
