ToddAndMargo via perl6-users writes:
> On 10/29/21 18:42, Ralph Mellor wrote:
>
> Hi Raiph,
>
> I was trying to get the whole thing in Raku.
> the "from perl 5" is cool stuff for sure, but
> I would still be maintaining 90% of the code in
> perl 5. So it is better just to stay in p5.
Which part of
On 10/30/21 02:23, chohag via perl6-users wrote:
ToddAndMargo via perl6-users writes:
On 10/29/21 18:42, Ralph Mellor wrote:
Hi Raiph,
I was trying to get the whole thing in Raku.
the "from perl 5" is cool stuff for sure, but
I would still be maintaining 90% of the code in
perl 5. So it is bet
ToddAndMargo via perl6-users writes:
> On 10/30/21 02:23, chohag via perl6-users wrote:
> > Which part of the machinery around 'use' and ':from' is not Raku?
>
> That is Raku.
>
> The code it calls is not. I am trying to convert the
> code it calls to Raku.
Why when your computer is already doing
Recently I was golfing the "hyperfactorial," defined for a number 𝑛 as
𝑛**𝑛 × (𝑛-1)**(𝑛-1) × (𝑛-2)**(𝑛-2) × ... × 1. I created a quite
concise Raku function:
{ [*] [\*] $_...1 }
The only problem was that this function returns zero for a zero input,
whereas the hyperfactorial of 0 is supposed
On 10/30/21 10:52, chohag via perl6-users wrote:
ToddAndMargo via perl6-users writes:
On 10/30/21 02:23, chohag via perl6-users wrote:
Which part of the machinery around 'use' and ':from' is not Raku?
That is Raku.
The code it calls is not. I am trying to convert the
code it calls to Raku.
On Sat, Oct 30, 2021 at 5:03 AM ToddAndMargo via perl6-users
wrote:
>
> I was trying to get the whole thing in Raku.
Why are you rejecting the "whole Raku" solutions that have
been suggested to you in this thread?
Your original questions were:
* ftp client yet?
* Do we have a working ftp modul
Damn but I'm a sucker for punishment. :)
On Sun, Oct 31, 2021 at 12:14 AM ToddAndMargo via perl6-users
wrote:
>
> I think you misunderstand.
Fwiw I think you misunderstand.
If the penny doesn't begin to drop with this email I think
my head will explode. Or maybe my tail.
> The code I want to c
On Sat, Oct 30, 2021 at 8:38 PM Sean McAfee wrote:
>
> It worked! But I couldn't quite see how.
>
> Anyway, pretty cool!
I agree it's cool, at least in a golfing sense.
But is your explanation right?
The *range* operator (`..`), if the rhs is less than the left,
yields an empty list rather tha
On 10/30/21 19:08, Ralph Mellor wrote:
I don't understand what you are thinking.
Hi Ralph,
That is because I have not made myself clear enough.
Or maybe you are trying to expand to something greater
than I am asking. That is a hazard when dealing with
mensches that love to be helpful: scope
Hi All,
Without going into why (it is a secret), how do I turn
> my $x = sqrt 2
1.4142135623730951
into an array of integers?
@y[0] = 1
@y[1] = 4
@y[2] = 1
@y[3] = 4
@y[4] = 2
@y[5] = 1
etc.
Many thanks,
-T
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