hello everyone,
I made a mistake while replying to all of us so anwsers never reached
your boxes. I'll summerize in one answer:
Bill:
> Is it just even/odd elements that you want to separate out? If so, maybe
> .grep() is your friend here
I don't think it is: 0, 2 ... * seems to be
* closer to
Hi Marc,
My understanding is that ranges are pretty cheap to construct, and in any
case, the range @x[0..*-1] is just the index of all elements in @x. The
.grep() approach may be most useful if you have a function (e.g. %, %%, and
.is-prime shown below):
> (0...9)
(0 1 2 3 4 5 6 7 8 9)
> (0...9)[
Hi Bill,
When building a range that's an arithmetic or geometric progression, the
sequence operator is a little quicker to type. And thus also more likely to
be understood more quickly too.
> ('a' .. 'h')[(0..*-1).grep: * %% 2 ]
(a c e g)
> ('a' .. 'h')[ 0, 2 ... * ]
(a c e g)
> ('a' .. 'h')[(0.
