Oh, I'd been intending to explore that before sending but forgot. Thanks.
I currently think that's the best alternative to duplicating defaults, but
still more verbose and less intuitive than I'd hope for.
On Sat, Sep 5, 2015 at 12:57 AM Timo Paulssen wrote:
> Have you considered hash flattenin
# New Ticket Created by dakkar
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Example:
$ perl6 -e 'dd '
("a", "b")
$ perl6 -e 'dd <>'
"a"
"b"
$ perl6 -e 'dd
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This code::
role R[$a,$b] {}
role R2[$x] does R[1] {}
class C does R2[1] {}
C.new;
P
Some elaboration:
$ 6 'sub a(@a) { say @a.perl }; a ; a << a b >>'
===SORRY!=== Error while compiling -e
Calling a(Str, Str) will never work with declared signature (@a)
at -e:1
--> sub a(@a) { say @a.perl }; a ; ⏏a << a b >>
Liz
===
> On 05 Sep 2015, at 12:33, dakkar (via RT
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This code::
role R[$a,$b] {}
class C does R[1] {}
C.new;
Produces the error message::
One would expect an error message such as:
$ 6 'role R[$a,$b] {}; class C does R[1] {}'
===SORRY!===
No appropriate parametric role variant available for ‘R'
but even that message is rather LTA, as it doesn’t mention which parameters
were tried and which candidates are available.
Liz
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This::
'/tmp'.IO eqv '/tmp'.IO
returns ``False``.
Is this correct? Should IO behave like
> On 05 Sep 2015, at 16:06, dakkar (via RT)
> wrote:
>
> # New Ticket Created by dakkar
> # Please include the string: [perl #125998]
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> # https://rt.perl.org/Ticket/Display.html?id=125998 >
>
>
> This::
>
> '/tmp'.IO
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Given this code::
{
class Foo { has $.x }
multi sub infix:(Foo $a, Foo $b) {
I kind of think that's impossibly complex. What does it even mean for IO
objects to be value-equal? They represent unknowns in any case. Even if
they resolved to the same file, they might be read at different times and
have different contents. Or a write to one object may succeed and another
may no
On Sat Sep 05 07:47:24 2015, dakkar wrote:
> Given this code::
>
> {
> class Foo { has $.x }
>
> multi sub infix:(Foo $a, Foo $b) {
> say "won't get called";
> $a.x eqv $b.x
> }
> }
>
> multi sub infix:(Foo $a, Foo $b) {
> say "will get called";
> $a.x eqv $
Note that we’re talking really about IO::Path objects here, which is what .IO
generates.
And in that context, I think an object $a with a given abspath, would be eqv to
$b with the same abspath. Because that *is* the identifier on a file system,
is it not?
Liz
=
> On 05 Sep
Branch: refs/heads/master
Home: https://github.com/perl6/specs
Commit: 1ec7ab1ec91deec8f6c1b8494ba73bcbac3830ec
https://github.com/perl6/specs/commit/1ec7ab1ec91deec8f6c1b8494ba73bcbac3830ec
Author: Moritz Lenz
Date: 2015-09-05 (Sat, 05 Sep 2015)
Changed paths:
M S02-bi
Branch: refs/heads/master
Home: https://github.com/perl6/specs
Commit: 4c498440d7320c4e013382fcc1d4a9b6574fb673
https://github.com/perl6/specs/commit/4c498440d7320c4e013382fcc1d4a9b6574fb673
Author: Moritz Lenz
Date: 2015-09-05 (Sat, 05 Sep 2015)
Changed paths:
M S05-re
Branch: refs/heads/master
Home: https://github.com/perl6/specs
Commit: 650f0088de4c7a46dcd5f7c44f4f996357d109f7
https://github.com/perl6/specs/commit/650f0088de4c7a46dcd5f7c44f4f996357d109f7
Author: Moritz Lenz
Date: 2015-09-05 (Sat, 05 Sep 2015)
Changed paths:
M S03-op
# New Ticket Created by Moritz Lenz
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moritz@hack:~/p6/rakudo$ ./perl6-m --version
This is perl6 version 2015.07.1-717-ga6bb0ba
Branch: refs/heads/master
Home: https://github.com/perl6/specs
Commit: 558155b811176632b4e00366df2d40c5eeb89cfc
https://github.com/perl6/specs/commit/558155b811176632b4e00366df2d40c5eeb89cfc
Author: Moritz Lenz
Date: 2015-09-05 (Sat, 05 Sep 2015)
Changed paths:
M S04-co
# New Ticket Created by Larry Wall
# Please include the string: [perl #126003]
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> perl6-m -e 'multi sub foo(@array) { say @array }; foo("abc".comb)'
Cannot call foo(Seq);
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What I did
==
while ++$ < 3 { UNDO say 'undo'; say 'done' }
What I got
==
don
* mt1957 [2015-08-31 19:35]:
> I can not do the following;
> my Buf $b = 'abc'.encode;
> Type check failed in assignment to '$b'; expected 'Buf' but got 'utf8'
>
> But I can do this;
> my Buf $b = 'abc'.encode ~ Buf.new();
> Buf:0x<61 62 63>
>
> Does the concatenation convert utf8 into Buf? Will t
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