Author: masak
Date: 2010-08-10 11:47:45 +0200 (Tue, 10 Aug 2010)
New Revision: 31937
Modified:
docs/Perl6/Spec/S32-setting-library/Str.pod
Log:
[S32/Str] fixed thinko in &pack signature
Spotted by moritz++
Modified: docs/Perl6/Spec/S32-setting-library/Str.pod
=
Author: masak
Date: 2010-08-10 13:50:30 +0200 (Tue, 10 Aug 2010)
New Revision: 31938
Modified:
docs/Perl6/Spec/S32-setting-library/Str.pod
Log:
[S32/Str] nicer where clause for &pack
Reads better and is more amenable to compiler optimization. Suggested by
TheDamian++.
Modified: docs/Perl6/Spe
Author: moritz
Date: 2010-08-10 14:55:57 +0200 (Tue, 10 Aug 2010)
New Revision: 31939
Modified:
docs/Perl6/Spec/S32-setting-library/IO.pod
Log:
[S32::IO] update to new type names, remove some thinkos
Modified: docs/Perl6/Spec/S32-setting-library/IO.pod
=
# New Ticket Created by Moritz Lenz
# Please include the string: [perl #77134]
# in the subject line of all future correspondence about this issue.
# http://rt.perl.org/rt3/Ticket/Display.html?id=77134 >
15:49 < moritz_> rakudo: say 'abc' ~~ .say
15:49 <+p6eval> rakudo 4bd478: OUTPUT«abc1»
I've been running into all sorts of problems trying to take S02 at its word
that Int supports arbitrary precision. It *sort of* does. But there are the
edge cases where it doesn't. This might just be something that's not there
yet, and I understand, but I thought I should report it.
If exponentiat
Am 10.08.2010 01:11, schrieb Aaron Sherman:
I've been running into all sorts of problems trying to take S02 at its word
that Int supports arbitrary precision. It *sort of* does.
It does in Perl 6, but not in Rakudo (known limitation).
Moritz
# New Ticket Created by Michael Cartmell
# Please include the string: [perl #77126]
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# http://rt.perl.org/rt3/Ticket/Display.html?id=77126 >
mich...@wslx1:working> perl6 -v
This is Rakudo Perl 6, version 2010.07-47-g9fd5eaa
# New Ticket Created by Solomon Foster
# Please include the string: [perl #77138]
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# http://rt.perl.org/rt3/Ticket/Display.html?id=77138 >
colomon: star: subset ComplexNumeric of Numeric where { ($_ ~~ Real)
|| ($_ ~~ Complex
Hi,
some of this has been discussed on #perl6, so I'd like to give a brief
summary only:
Am 06.08.2010 17:53, schrieb Tadeusz Sośnierz:
While writing neutro (a working module installer, while waiting for
proto/pls, see [1]), and wandering around modules listed on
proto.perl6.org, I started wo
# New Ticket Created by Stephane Payrard
# Please include the string: [perl #77140]
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# http://rt.perl.org/rt3/Ticket/Display.html?id=77140 >
perl6
> say Nil.defined
1
>
--
cognominal stef
On Tue Aug 10 09:00:25 2010, cognominal wrote:
> perl6
> > say Nil.defined
> 1
It goes against my expectations too, but it's spec. Rejecting ticket.
Hi there...
New to the list and getting to understand perl6 after a bit of a hiatis from
the Perl world.
I'm working my way through the new grammar syntax trying to implement some
useful modules, and was wondering if there is a mechanism within the grammar
constructs to allow two rules to appl
Hi,
philippe.beauch...@bell.ca wrote:
> rule TOP
> {
> ^
> [
> & *
> &
> ]
> $
> }
The & syntax is specced, but it's not yet implemented in Rakudo.
But note that is a zero-width assertion, so your e
Great! That does it. Thanks. :)
I realized my error on the anchors after sending... but didn't think of the *
on the grouping.
On the & operator... are you saying that it would operate basically as
expected... allowing sets of rules and'ed rather than or's with the | ?
--- Phil
-Origin
philippe.beauch...@bell.ca wrote:
> On the & operator... are you saying that it would operate basically as
> expected...
> allowing sets of rules and'ed rather than or's with the | ?
Yes, with the limitation that both parts separated by & have to match
the same length of string, so that for exam
Back to your original advice...
> If you want to match an alphabetic string which does not include 'abc'
> anywhere, you can write this as
>
> ^ [ ]* $
I presume this only works here because is one character... if instead
of I used anything more complicated
(for example)
token name
{
# New Ticket Created by Wenzel Peppmeyer
# Please include the string: [perl #77144]
# in the subject line of all future correspondence about this issue.
# http://rt.perl.org/rt3/Ticket/Display.html?id=77144 >
my $s = 'abcd'; while $s ~~ m:g/(.)/ { print $0 };
Neither works nor does it give a
On Tue Aug 03 23:28:39 2010, masak wrote:
> the &mkdir builtin creates a directory with mode 000 per
> default. do we really have the balance between security and
> least-surprise right in this case?
> sounds like a flat out bug to me
> should be 777
> * masak submits rakudobug
This has been fi
# New Ticket Created by Stephane Payrard
# Please include the string: [perl #77146]
# in the subject line of all future correspondence about this issue.
# http://rt.perl.org/rt3/Ticket/Display.html?id=77146 >
I edited my garbled sentences.
[15:28:22] I know that a match is both an array an
I edited my garbled sentences.
[15:28:22] I know that a match is both an array and a
hash and that both containers have a .keys method. But I would expect
.keys for a Match to return a list of the named reductions
[15:28:37] rakudo: grammar A { token TOP { }; token
a { a } }; class A::A {
On Tue, Aug 10, 2010 at 9:00 PM, wrote:
> Once the & operator is in rakudo, though... I gather I /could/ do something
> like the following
>
> ^ [ * & ] $
>
> And this would in effect ensued that the sequence "abc" doesn't exist
> anywhere across the match for
>
>
> Is this correct?
>
Not
On Tue, Aug 10, 2010 at 10:39 AM, Moritz Lenz wrote:
> Am 10.08.2010 01:11, schrieb Aaron Sherman:
>
> I've been running into all sorts of problems trying to take S02 at its
>> word
>> that Int supports arbitrary precision. It *sort of* does.
>>
>
> It does in Perl 6, but not in Rakudo (known li
Thanks Moritz,
it just felt like I should be able to leave out the "+ 0i" since that's
how I wrote them when studying maths;)
Thanks for the shiny new toy;)
Regards,
Michael
On 11/08/10 00:59, Moritz Lenz via RT wrote:
On Tue Aug 10 01:28:11 2010, a_...@bigpond.net.au wrote:
my Complex $c
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