On Mon Mar 29 08:41:18 2010, masak wrote:
> $ cat A.pm
> grammar A {
> }
>
> $ cat B.pm
> class B;
>
> method foo() {
> use A;
> }
>
> $ perl6 B.pm
> You can not add a Method to a module; use a class, role or grammar
> [...]
>
> I'm assuming that the above should work. (It does in alpha, an
On Mon Jul 13 17:50:45 2009, minimiscie...@gmail.com wrote:
> Rakudo can't seem to parse [=>]:
>
> $ perl6
> > ([=>] 42, 23).perl.say
> Syntax error at line 1, near "([=>] 42, "
> in Main (src/gen_setting.pm:0)
>
> However, "(42 => 23).perl.say" works fine.
>
> This problem w
On Tue Jul 14 02:59:47 2009, masak wrote:
> std: regex foo($a) { . }
> std 27548: OUTPUT«ok 00:02 38m»
> ooh!
> rakudo: regex foo($a) { . }
> rakudo 147b3d: OUTPUT«Malformed regex definition at line 2,
> near "foo($a) {" [...]
> * masak submits rakudobug
Works and also has some tests (though
# New Ticket Created by Richard Hainsworth
# Please include the string: [perl #74050]
# in the subject line of all future correspondence about this issue.
# http://rt.perl.org/rt3/Ticket/Display.html?id=74050 >
finanalyst: perl6: my @v=2,5; say ( map {; $^b => $^a }, @v ).perl
p6eval: rakudo
no
On Tue, Mar 30, 2010 at 9:16 AM, Moritz Lenz via RT <
perl6-bugs-follo...@perl.org> wrote:
> On Thu Nov 05 10:43:03 2009, schwenn wrote:
> > Dear perl6-bugs
> >
> > No trouble svn'ng, configuring and building latest parrot 42272, nor
> in git
> > pull'ng latest rakudo. No trouble configuring
