John Williams wrote:
> Back in October I suggested that $a ^+= @b would act like reduce,
> but in discussion
> it was decided that it would act like length
> I now pose the question: Is ^+= a "hyper assignment operator" or an
> "assignment hyper operator"?
> with a scalar involved
> the me
Apologies for trying to resuscitate this old horse, but a new idea
occurred to me.
Back in October I suggested that $a ^+= @b would act like reduce,
but in discussion
it was decided that it would act like length, by the interpretation:
$a ^+= @b
$a = $a ^+ @b
$a = ($a, $a, $a, ..
