On Tue, Aug 23, 2005 at 03:48:03PM -0400, Sam Ruby wrote:
> How will Perl6 evaluate defaults?
I would like to help with this question, but I can't, and in general
p6i won't be the right place to ask. Nobody knows the final form of
Perl 6; nobody knows the currently understood form of Perl 6 excep
On Tue, Aug 23, 2005 at 03:48:03PM -0400, Sam Ruby wrote:
: How will Perl6 evaluate defaults?
:
: Like Python:
:
: global x
: x=1
: def f(p1=x):
: return p1
: x=2
: print f()
:
: or like Ruby:
:
: $x=1
: def f(p1=$x)
: return p1
: end
: $x=2
: puts f()
By default, d
How will Perl6 evaluate defaults?
Like Python:
global x
x=1
def f(p1=x):
return p1
x=2
print f()
or like Ruby:
$x=1
def f(p1=$x)
return p1
end
$x=2
puts f()
- Sam Ruby
P.S. The former prints "1", the latter, "2".
