At 11:51 AM +0100 1/11/03, Leopold Toetsch wrote:
Brent Dax wrote:
Steve Fink:
# -memcpy(targ, ret->strstart, ret->bufused);
# -targ[ret->bufused + 1] = '\0';
# +memcpy(targ, ret->strstart, ret->strlen);
# +targ[ret->strlen] = '\0';
I could be wrong, but isn't strlen the
Steve Fink wrote:
On Jan-11, Leopold Toetsch wrote:
Brent Dax wrote:
Steve Fink:
# -memcpy(targ, ret->strstart, ret->bufused);
# -targ[ret->bufused + 1] = '\0';
# +memcpy(targ, ret->strstart, ret->strlen);
# +targ[ret->strlen] = '\0';
I could be wrong, but isn't strl
On Jan-11, Leopold Toetsch wrote:
> Brent Dax wrote:
>
> >Steve Fink:
> ># -memcpy(targ, ret->strstart, ret->bufused);
> ># -targ[ret->bufused + 1] = '\0';
> ># +memcpy(targ, ret->strstart, ret->strlen);
> ># +targ[ret->strlen] = '\0';
> >
> >I could be wrong, but isn't str
Brent Dax wrote:
Steve Fink:
# -memcpy(targ, ret->strstart, ret->bufused);
# -targ[ret->bufused + 1] = '\0';
# +memcpy(targ, ret->strstart, ret->strlen);
# +targ[ret->strlen] = '\0';
I could be wrong, but isn't strlen the length in characters rather than
the length in byt
Steve Fink:
# -memcpy(targ, ret->strstart, ret->bufused);
# -targ[ret->bufused + 1] = '\0';
# +memcpy(targ, ret->strstart, ret->strlen);
# +targ[ret->strlen] = '\0';
I could be wrong, but isn't strlen the length in characters rather than
the length in bytes?
--Brent Dax <[