On 1/20/06, Juerd <[EMAIL PROTECTED]> wrote:
> Note, by the way, that JS has "primitive" strings, and Strings, only the
> latter being objects. Fortunately for us, though, a string is
> automatically promoted to a String when the string is USED AS an object.
In other words, according to userland,
Rob Kinyon skribis 2006-01-19 20:54 (-0500):
> > > There are no references in Perl6.
> > Is your Perl the same as that of other people on this list? :)
> There are no references in Perl6 in the way Perl5 conceives of references.
There are references in Perl 6.
Do note that @foo evaluates to a ref
On 1/19/06, Juerd <[EMAIL PROTECTED]> wrote:
> Rob Kinyon skribis 2006-01-19 16:10 (-0500):
> > There are no references in Perl6.
> I have to admit, though, that I've never seen this statement, or
> anything implying it. It's entirely new to me.
>
> Is your Perl the same as that of other people on
On Jan 19, 2006, at 5:19 PM, Jonathan Scott Duff wrote:
On Thu, Jan 19, 2006 at 11:07:49PM +0100, Juerd wrote:
Stevan Little skribis 2006-01-19 16:59 (-0500):
2) what if the role conflicts with other roles being does-ed by Foo?
Debugging hell there.
Very good point.
Aren't role conflicts r
On Jan 19, 2006, at 5:09 PM, Juerd wrote:
Stevan Little skribis 2006-01-19 17:06 (-0500):
This turns "everything is an object" into "everything can be used
with
OO syntax", which I think is more true
Alternatively and simultaneously, "everything represents an object".
Well, if "everything is
On Thu, Jan 19, 2006 at 11:07:49PM +0100, Juerd wrote:
> Stevan Little skribis 2006-01-19 16:59 (-0500):
> > 2) what if the role conflicts with other roles being does-ed by Foo?
> > Debugging hell there.
>
> Very good point.
Aren't role conflicts resolved at composition time (possibly by
failur
Stevan Little skribis 2006-01-19 17:06 (-0500):
> >This turns "everything is an object" into "everything can be used with
> >OO syntax", which I think is more true
> >Alternatively and simultaneously, "everything represents an object".
> Well, if "everything is NOT an object", then the synopsis nee
Stevan Little skribis 2006-01-19 16:59 (-0500):
> But we cannot automagically inject a role into a class, for a number
> of reasons.
> 1) thats just plain evil
But then, so is bless, so the two can play along.
> 2) what if the role conflicts with other roles being does-ed by Foo?
> Debugging
Juerd,
On Jan 19, 2006, at 4:21 PM, Juerd wrote:
Juerd skribis 2006-01-19 22:18 (+0100):
Could you live with @foo being an array, and @foo in scalar context
returning a reference to that array? And with arrays being
interfaces to
underlying Arrays, which are objects, which makes arrays non-o
Juerd,
On Jan 19, 2006, at 4:10 PM, Juerd wrote:
Stevan Little skribis 2006-01-19 15:45 (-0500):
class Foo {
method new ($class: %params) {
$class.bless(%params);
Wouldn't that be %params.bless($class), or more directly,
%params.blessed = $class?
Nope, according to S12:
On Jan 19, 2006, at 4:10 PM, Rob Kinyon wrote:
Packages don't have anything to do with the class
system.
Actually ^Class.isa(^Package) ;)
Stevan
Juerd skribis 2006-01-19 22:18 (+0100):
> Could you live with @foo being an array, and @foo in scalar context
> returning a reference to that array? And with arrays being interfaces to
> underlying Arrays, which are objects, which makes arrays non-objects
> that can be used *as* objects?
This turn
Rob Kinyon skribis 2006-01-19 16:10 (-0500):
> There are no references in Perl6.
When you said that one can't use OO in Perl 5, I had something to say
because it's a recurring subject.
I have to admit, though, that I've never seen this statement, or
anything implying it. It's entirely new to me.
On Thursday 19 January 2006 13:10, Rob Kinyon wrote:
> &bless was a brilliant idea for Perl5. It's wrong for Perl6.
Perhaps you meant to write "Tagging a reference with a package name worked for
Perl 5. It's wrong for Perl 6."
Certainly I can agree with that.
Yet this whole discussion feels l
To further extend Steve's argument (which I wholeheartedly agree
with), I wanted to point out one thing: &bless has nothing to do with
OO programming as conceived of in Perl6. It does one thing and only
one thing:
- tag a reference with a package name.
This is used in a few places:
- to d
Stevan Little skribis 2006-01-19 15:45 (-0500):
> class Foo {
> method new ($class: %params) {
> $class.bless(%params);
Wouldn't that be %params.bless($class), or more directly,
%params.blessed = $class?
> This *won't* work the same in Perl 6 though. This is because,
> what is
Hello,
I am forking this off the "Perl 6 OO and bless" thread since that
seems to have gotten bogged down in what it all means to Perl 5
interoperability. This was not really my intent with the original
thread, but I think it is still a fruitful discussion so I will re-
make my original po
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