On 1/3/19 1:52 AM, JJ Merelo wrote:
El mié., 2 ene. 2019 a las 21:04, ToddAndMargo via perl6-users
(mailto:perl6-us...@perl.org>>) escribió:
Dear Perl 6 Developers,
Fedora 29, x64
Xfce 4.13
$ perl6 -v
This is Rakudo version 2018.11 built on MoarVM version
On 1/2/19 4:00 PM, Brad Gilbert wrote:
You can only list one type as a return type.
If there were a hypothetical Tuple type:
sub AddThree( Int $a, Int $b, Int $c --> Tuple[Str, Int] {
my Int $d = $a + $b + $c;
return Tuple[Str,Int].new( "a+b+c=", $d );
}
I drew the
You can only list one type as a return type.
If there were a hypothetical Tuple type:
sub AddThree( Int $a, Int $b, Int $c --> Tuple[Str, Int] {
my Int $d = $a + $b + $c;
return Tuple[Str,Int].new( "a+b+c=", $d );
}
my Int $X = 0;
my Int $Y = 0;
my Str $Z;
On 1/2/19 2:27 PM, ToddAndMargo via perl6-users wrote:
On 1/2/19 2:11 PM, Simon Proctor wrote:
Have you tried defining your return values in the signature?
sub AddThree( Int $a, Int $b, Int $c --> Int) {...}
With this the compiler knows what your function is supposed to return
and can earn yo
On 1/2/19 2:11 PM, Simon Proctor wrote:
Have you tried defining your return values in the signature?
sub AddThree( Int $a, Int $b, Int $c --> Int) {...}
With this the compiler knows what your function is supposed to return
and can earn you in advance.
I did and it blew up in my face so I sto
Have you tried defining your return values in the signature?
sub AddThree( Int $a, Int $b, Int $c --> Int) {...}
With this the compiler knows what your function is supposed to return and
can earn you in advance.
On Wed, 2 Jan 2019, 20:04 ToddAndMargo via perl6-users Dear Perl 6 Developers,
>
>
Dear Perl 6 Developers,
Fedora 29, x64
Xfce 4.13
$ perl6 -v
This is Rakudo version 2018.11 built on MoarVM version
2018.11 implementing Perl 6.d.
I am constantly improving (changing things) in my subs,
etc.. As such, the things I return often change.
Because of this, I have a found so
