[perl #123835] Cannot use 'is rw' on optional parameter

2017-12-03 Thread Aleks-Daniel Jakimenko-Aleksejev via RT
Still reproducible (2017.11,HEAD(e5b660e)) I don't know if it's NYI or @LARRY. I'd put LARRY first, and then one of the LARRYs can turn it into a NYI. On 2015-08-05 15:25:57, barto...@gmx.de wrote: > The relevant sentences from the design docs (S06, introduced with > commit 7846594ee4): > > "Sinc

[perl #123835] Cannot use 'is rw' on optional parameter

2015-08-05 Thread Christian Bartolomaeus via RT
The relevant sentences from the design docs (S06, introduced with commit 7846594ee4): "Since this option [is rw] forces an argument to be required, it cannot coexist with the ? mark to make an argument optional. (It may, however, be used with = indicating a default, but only if the default expr

[perl #123835] Cannot use 'is rw' on optional parameter

2015-02-15 Thread via RT
# New Ticket Created by Adrian Kreher # Please include the string: [perl #123835] # in the subject line of all future correspondence about this issue. # https://rt.perl.org/Ticket/Display.html?id=123835 > I tried 'sub f($x is rw = 60)', STD parses it but rakudo prohibits it. 'is copy' works.