On 4/29/24 17:57, Patrick R. Michaud wrote:
Perhaps not really what you're intending, but here's how I'd start:
$ raku -e 'my $x="1.2.3.4"; $x ~~ s!\d+$!0/24!; say $x;'
1.2.3.0/24
The pattern part of the substitution matches all of the digits at the end of the string
(\d+$), then rep
Perhaps not really what you're intending, but here's how I'd start:
$ raku -e 'my $x="1.2.3.4"; $x ~~ s!\d+$!0/24!; say $x;'
1.2.3.0/24
The pattern part of the substitution matches all of the digits at the end of
the string (\d+$), then replaces them with the string "0/24". Everything p
On 4/29/24 17:42, ToddAndMargo via perl6-users wrote:
Hi All,
I thought I understood ^ and ? used in a regex'es,
but I don't.
^ means from the beginning and ? from the end.
I am trying to put together an example
of how to use them:
I have
1.2.3.4
I want
1.2.3.0/24
So Far I have (no
Hi All,
I thought I understood ^ and ? used in a regex'es,
but I don't.
^ means from the beginning and ? from the end.
I am trying to put together an example
of how to use them:
I have
1.2.3.4
I want
1.2.3.0/24
So Far I have (not working):
raku -e 'my $x="1.2.3.4"; $x~~s/ (.*) $(Q
