Re: regex: how to I pick out items in the middle?

On Sat, Oct 29, 2022 at 7:29 PM ToddAndMargo via perl6-users < perl6-us...@perl.org> wrote: > >> On Sat, Oct 29, 2022 at 6:46 PM ToddAndMargo via perl6-users > >> mailto:perl6-us...@perl.org>> wrote: > >> > >> Hi All, > >> > >> With a regex, how do I pick out items in the middle of the str

Re: regex: how to I pick out items in the middle?

On Sat, Oct 29, 2022 at 6:46 PM ToddAndMargo via perl6-users mailto:perl6-us...@perl.org>> wrote: Hi All, With a regex, how do I pick out items in the middle of the string? Two from the beginning or two from the end? 4] > my Str $y="xx"; $y ~~ s/ $([.*-2]) "x"/Q/; print $

Re: regex: how to I pick out items in the middle?

In the Raku REPL: $ raku Welcome to Rakudo™ v2022.07. Implementing the Raku® Programming Language v6.d. Built on MoarVM version 2022.07. To exit type 'exit' or '^D' [0] > #beginning Nil [1] > my Str $y="xx"; S/^ x ** 2 /QQ/.say given $y; QQ [1] > #inner Nil [2] > my Str $y="xx"; S/^ [

regex: how to I pick out items in the middle?

Hi All, With a regex, how do I pick out items in the middle of the string? Two from the beginning or two from the end? 4] > my Str $y="xx"; $y ~~ s/ $([.*-2]) "x"/Q/; print $y ~ "\n" ===SORRY!=== Error while compiling: Malformed postfix call --> my Str $y="xx"; $y ~~ s/ $([.*⏏-2

Re: how do I do a literal string in the target of a regex?

On 10/29/22 14:28, ToddAndMargo via perl6-users wrote: On 10/29/22 13:07, Elizabeth Mattijsen wrote: > $ echo "a/b/c/d" | raku -ne 'say .subst("/", Q/\\\/, :g)' > Hi Elizabeth, Thank you for the subst workaround! I created a keep of the subst. Got to love Raku. 101 ways of doing everything

Re: how do I do a literal string in the target of a regex?

On 10/29/22 13:02, ToddAndMargo via perl6-users wrote: Hi All, I am trying to change / into \\\ This works: $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/])|\\|;print $x ~ "\n"' a\\\b\\\c\\\d But this does not: $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/

Re: how do I do a literal string in the target of a regex?

On 29 Oct 2022, at 23:28, ToddAndMargo via perl6-users wrote: On 29 Oct 2022, at 22:02, ToddAndMargo via perl6-users wrote: Hi All, I am trying to change / into \\\ This works: $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/])|\\|;print $x ~ "\n"' a\\\b\\\c\\\d

Re: how do I do a literal string in the target of a regex?

/ 'literal string in target' / > On 29 Oct 2022, at 23:28, ToddAndMargo via perl6-users > wrote: > > >>> On 29 Oct 2022, at 22:02, ToddAndMargo via perl6-users >>> wrote: >>> >>> Hi All, >>> >>> I am trying to change >>> >>> / >>> >>> into >>> >>> \\\ >>> >>> This works: >>> >

Re: how do I do a literal string in the target of a regex?

On 29 Oct 2022, at 22:02, ToddAndMargo via perl6-users wrote: Hi All, I am trying to change / into \\\ This works: $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/])|\\|;print $x ~ "\n"' a\\\b\\\c\\\d But this does not: $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s

Re: how do I do a literal string in the target of a regex?

$ echo "a/b/c/d" | raku -ne 'say .subst("/", Q/\\\/, :g)' > On 29 Oct 2022, at 22:02, ToddAndMargo via perl6-users > wrote: > > Hi All, > > I am trying to change > > / > > into > > \\\ > > This works: > > > $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/])|\\|;print $x ~

how do I do a literal string in the target of a regex?

Hi All, I am trying to change / into \\\ This works: $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/])|\\|;print $x ~ "\n"' a\\\b\\\c\\\d But this does not: $ echo "a/b/c/d" | raku -ne 'my $x=$_; $x~~s:g|$(Q[/])|Q[\\\]|;print $x ~ "\n"' aQ[\]bQ[\]cQ[\]d How do I