Re: How do I use ~ with Regex syntax?

2019-08-30 Thread ToddAndMargo via perl6-users
On Fri, Aug 30, 2019 at 8:26 PM ToddAndMargo via perl6-users mailto:perl6-us...@perl.org>> wrote: Hi All, Yes, I know to just put the variable inside the quote, but I'd still like to know how to do it outside the quote; $NewPage ) ~~ s/ .*? "Full Change Log for Version " ~ $Ye

Re: How do I use ~ with Regex syntax?

2019-08-30 Thread Paul Procacci
Drop the '~'. $b ~~ s/ .*? "In the year " $a//; ~Paul On Fri, Aug 30, 2019 at 8:26 PM ToddAndMargo via perl6-users < perl6-us...@perl.org> wrote: > Hi All, > > Yes, I know to just put the variable inside the quote, but > I'd still like to know how to do it outside the quote; > > > $NewPage ) ~

Re: core dump

2019-08-30 Thread ToddAndMargo via perl6-users
On 8/9/19 3:41 PM, ToddAndMargo via perl6-users wrote: Hi All, Fedora 30 rakudo-0.2019.03-2.fc30.x86_64 I have a weird question.  I need to simulate a core dump under a bash (ulimit) shell. Any of you guys know who to get Perl to crash with a core dump? I need to prove that core dumps are not

How do I use ~ with Regex syntax?

2019-08-30 Thread ToddAndMargo via perl6-users
Hi All, Yes, I know to just put the variable inside the quote, but I'd still like to know how to do it outside the quote; $NewPage ) ~~ s/ .*? "Full Change Log for Version " ~ $YearRev //; --> Full Change Log for Version " ~ $YearRev⏏ //; Couldn't find terminator / at /home/linuxutil/./Get