[perl #130442] [REGRESSION] [LTA] redo without a loop no longer prints the line number, also claims it is a compile-time error (redo)

2019-03-01 Thread Aleks-Daniel Jakimenko-Aleksejev via RT
Moved to https://github.com/rakudo/rakudo/issues/2725 On 2016-12-29 14:43:03, alex.jakime...@gmail.com wrote: > Of course, same thing with “next” and “last” (is there anything else?) > > On 2016-12-29 09:13:24, alex.jakime...@gmail.com wrote: > > Code: > > say 42; redo > > > > > > Result (2015.12,

Re: .payload

2019-03-01 Thread ToddAndMargo via perl6-users
On 3/1/19 11:58 AM, ToddAndMargo via perl6-users wrote: On 2/28/19 3:46 AM, ToddAndMargo via perl6-users wrote: Follow up.  Thank yo for the Help!  My rewrite: CATCH {    # Reference: https://docs.perl6.org/language/exceptions#Catching_exceptions    my $Message = .message;    my $Message2

Re: .payload

2019-03-01 Thread ToddAndMargo via perl6-users
On 2/28/19 3:46 AM, ToddAndMargo via perl6-users wrote: Follow up. Thank yo for the Help! My rewrite: CATCH { # Reference: https://docs.perl6.org/language/exceptions#Catching_exceptions my $Message = .message; my $Message2; # for $Payload.comb -> $y { print "$y=", ord( $y ), "